如何使用用戶輸入指定範圍內需要的數量

Question

我需要用戶輸入來指定要在範圍內打印的數量。
我有下面的代碼：

i = 0; 
start_char = 65 
end_char = 65 
x = input("Enter numbers of plates:") 
while (i < int(x)): 
    if i%26 == 0 and i!= 0: 
      end_char = (65) 
      start_char += 1 

      print((chr(start_char))+(chr(end_char))) 
      end_char =end_char + 1 
      i = i + 1 
    for plate_code in (range(1000)): 
     print(str(plate_code) + ((chr(start_char))+(chr(end_char)))) 

Answer 1

你增加i只是內部的if以來i = 0開始，你的代碼永遠不會進入if和stucks在一個無限循環。

在if之外移動i = i + 1。

while (i < int(x)): 
    if i%26 == 0 and i!= 0: 
      end_char = (65) 
      start_char += 1 

      print((chr(start_char))+(chr(end_char))) 
      end_char =end_char + 1 
    i = i + 1 #move incrementation outside of if 
    for plate_code in (range(1000)): 
     print(str(plate_code) + ((chr(start_char))+(chr(end_char)))) 

Answer 2

只是不要試圖重塑for循環：

def main(): 
    start_char = end_char = 65 
    plate_count = int(input('Enter numbers of plates:')) 
    for i in range(plate_count): 
     if i and i % 26 == 0: 
      end_char = 65 
      start_char += 1 
     print(chr(start_char) + chr(end_char)) 
     end_char += 1 
     for plate_code in range(1000): 
      print('{}{}{}'.format(plate_code, chr(start_char), chr(end_char))) 


if __name__ == '__main__': 
    main() 

Alternativly使用標準庫的力量：

from itertools import islice, product 
from string import ascii_uppercase 


def main(): 
    plate_count = int(input('Enter numbers of plates: ')) 
    for start_char, end_char in islice(
     product(ascii_uppercase, ascii_uppercase), plate_count 
    ): 
     print('{}{}'.format(start_char, end_char)) 
     for plate_code in range(1000): 
      print('{}{}{}'.format(plate_code, start_char, end_char)) 


if __name__ == '__main__': 
    main()