搜索SQL查詢這是真的

Question

我有一個很好的搜索查詢，但我需要它只顯示結果visible = true。這就是需要添加到查詢中，我只是不知道如何正確執行。這是查詢。

$查詢= $ mysqli->查詢（「選擇 ID，姓名，公司，城市FROM人WHERE 名LIKE '％$ mysearchString％' OR 公司LIKE '％$ mysearchString％' OR 鎮LIKE'％$ mysearchString％'ORDER BY name DESC LIMIT 100「）;

$ mysearchString var只是一個消毒過的$_GET['s']。

Answer 1

SELECT id,name,company,town 
FROM people WHERE 
(name LIKE '%$mysearchString%' 
OR company LIKE '%$mysearchString%' 
OR town LIKE '%$mysearchString%') 
AND visible = true 
ORDER BY name DESC LIMIT 100 

Answer 2

$query = $mysqli->query("SELECT id,name,company,town FROM people WHERE (name LIKE '%$mysearchString%' OR company LIKE '%$mysearchString%' OR town LIKE '%$mysearchString%') AND visible = true ORDER BY name DESC LIMIT 100");