雖然循環不打印正確的猜字遊戲

Question

如何讓循環工作，以便它會在你正確的時候結束並且如果你弄錯了再問這個問題？ 當我猜錯兩次或更多次時，無論發生什麼事，總會說錯。

import random; 
import sys; 
x = random.randint(1, 100); 
print(x); 
guess = int(input("Guess a number 1 to 100")); 
if guess == x: 
     print("correct"); 
     sys.exit() 
while guess != x: 
    print("wrong"); 
    int(input("Guess a number 1 to 100")); 
    print(x); 
    if guess == x: 
     print("Correct"); 
     sys.exit() 

另外什麼函數記錄它循環的次數。例如，如果我猜錯了10次，然後我要打印，我打進了10

Answer 1

你忘了周圍的分配，第二次在該guess變量

while guess != x: 
    print("wrong"); 
    guess = int(input("Guess a number 1 to 100")); #look here 
    print(x); 
    if guess == x: 
     print("Correct"); 
     sys.exit() 

Answer 2

失蹤「的猜測=」循環中的輸入行。要記錄次數，只需在循環中增加一個變量即可。

[附錄]

import random; 
import sys; 
x = random.randint(1, 100); 
print(x); 
count = 1 
guess = int(input("Guess a number 1 to 100: ")); 
while guess != x: 
    count += 1 
    guess = int(input("Wrong\nGuess a number 1 to 100: ")); 
print("Correct - score = "+str(100./count)+"%"); 
sys.exit(0) 

Answer 3

其實你應該改變你的代碼：

import random 
x=random.randint(1,100) 
score=0 
while True: 
    guess=int(input("Guess a number 1 to 100: ")) 
    if guess==x: 
     print ("Correct!") 
     break 
    else: 
     print ("Not correct!") 
     score+=1 
print ("your answers was wrong {} times.".format(score)) 

更好的語句，少的代碼。乾杯!