我一直在這一整天工作,直到晚上8點仍然沒有運氣。我想知道你們是否可以給我一些修復它的建議。我正在爲大學建立一個Upload - gif共享系統。分頁數據庫查詢困境
這裏是我的代碼嗎 -
<?php
ini_set('display_errors',1);
error_reporting(E_ALL);
mysql_connect("localhost","root","root") or die("Top Query");
mysql_select_db("UPLOAD") or die(mysql_error());
$count_query = mysql_query("SELECT NULL FROM details");
$count = mysql_num_rows($count_query);
//pagination
if(isset($_GET['page'])){
$page = preg_replace("#[^0-9]#","",$_GET['page']);
}else{
$page= 1;
}
$perPage = 5;
$lastPage = ceil($count/$perPage);
if($page < 1){
$page = 1;
}else if($page > $lastPage){
$page = $lastPage;
}
$limit = "LIMIT " .($page -1) * $perPage . ", $perPage";
//Query and gifs
$query = mysql_query("SELECT * FROM details ORDER BY date_added DESC") or die("2nd Query");
//Puts it into an array
$pagination="";
if($lastPage != 1){
if($page != $lastPage){
$next = $page + 1;
$pagination.='<a href="index.php?page='.$next.'">More</a>';
}
if($page != 1){
$prev = $page - 1;
$pagination.='<a href="index.php?page='.$prev.'">Back</a>';
}
}
?>
然後在HTML輸出 -
<?php
while($info = mysql_fetch_array($query)){
$shortlink = "<a href=uploads/".$info['photo'].">".$info['photo']." </a>" ;
//Outputs the image and other data
echo "<article class='upload-post'>" . "<div class='crop'>";
echo "<a href=uploads/".$info['photo'].">";
echo "<img class='scale-with-grid' src=uploads/".$info['photo'] .">"."</a>";
echo "</div>";
echo "".$info['name'] . "<br/>";
echo "Reaction ".$info['reaction'] ."<br/>";
echo "In " .$info['category'] ." <br/>";
echo "On " .$info['date_added'] ." <br/>";
echo "Link: $shortlink";
echo "</article>";
}
?>
<?php echo $pagination;?>
我的網頁,但之間切換其不限制頁面上顯示的帖子的數量。我非常感謝這份幫助,因爲截止日期並不太遙遠。 預先感謝一堆!
你設置'$ limit',但你似乎並不被用它做任何事情。 – andrewsi 2013-05-02 19:11:40
[**請不要在新代碼中使用'mysql_ *'函數**](http://bit.ly/phpmsql)。他們不再被維護[並且被正式棄用](http://j.mp/XqV7Lp)。看到[**紅框**](http://j.mp/Te9zIL)?學習[*準備的語句*](http://j.mp/T9hLWi),並使用[PDO](http://php.net/pdo)或[MySQLi](http://php.net/ mysqli) - [這篇文章](http://j.mp/QEx8IB)將幫助你決定哪個。 – Kermit 2013-05-02 19:12:17