新的層次

Question

標識鍵假設我的源代碼看起來像

X1 H_ID l1_no l2_no l3_no 
20 1  2  12  42 
20 1  6  16  42 
20 1  1  19  41 
20 1  5  15  41 

我的查找表看起來像

X1 H_ID l1_no l1_key l2_no l2_key l3_no l3_key 
20 1  4  104   14  114   44  144 
20 1  3  103   13  113   43  143 
20 1  1  101   11  111   41  141 
20 1  2  102   12  112   42  142 

在這種情況下，我的記錄被視爲僅更新，如果我有一個完整的匹配和完整的密鑰將被保留。 如果它不匹配任何列，則將其視爲插入。 棘手的部分是甚至插入，每個層次級別必須檢查和密鑰必須保留匹配的位。

例如 假設我有1-> 11-> 14已經 和我確認1-> 11-> 15，則它必須是插入記錄，但對於圖1和11中的密鑰必須被保留和15它必須生成

此外，如果我得到一個1-> 12-> 14那麼在這種情況下，該記錄將被視爲一個插入和密鑰必須只保留1和新密鑰必須生成12和14

我能想到的一種可能的解決方案是通過將數據集視爲2D矩陣來爲每個級別進行左連接。但它不是一個好方法。

WITH lookup (x1, h_id, l1_no, l1_key, l2_no, l2_key,l3_no,l3_key) AS 
     (SELECT 20, 1, 1, 101, 11, 111, 41, 141 FROM sys.dual UNION ALL 
      SELECT 20, 1, 2, 102, 12, 112, 42, 142 FROM sys.dual UNION ALL 
      SELECT 20, 1, 3, 103, 13, 113, 43, 143 FROM sys.dual UNION ALL 
      SELECT 20, 1, 4, 104, 14, 114, 44, 144 FROM sys.dual), 
       dwh_keys AS 
     (SELECT x1, h_id, MAX(l1_key) mk1, MAX(l2_key) mk2, MAX(l3_key) mk3 
      FROM lookup GROUP BY 1,2) , 
    src (x1, h_id, l1_no, l2_no, l3_no) AS 
     (SELECT 20, 1, 1, 19, 41 FROM sys.dual UNION ALL 
      SELECT 20, 1, 2, 12, 42 FROM sys.dual UNION ALL 
      SELECT 20, 1, 5, 15, 41 FROM sys.dual UNION ALL 
      SELECT 20, 1, 6, 16, 42 FROM sys.dual), 
    stg1 AS 
     (SELECT  b.*, 
         CASE WHEN a.x1 IS NOT NULL THEN 'U' ELSE 'I' END AS delta_type 
      FROM  src b LEFT OUTER JOIN lookup a ON a.x1 = b.x1 AND a.h_id = b.h_id 
      AND a.l1_no = b.l1_no AND a.l2_no = b.l2_no AND a.l3_no = b.l3_no) 
SELECT  a.*, 
     CASE WHEN delta_type = 'I' AND b.l1_no IS NULL THEN mk1 + ROW_NUMBER () OVER (ORDER BY delta_type) ELSE b.l1_key END AS new1_key, 
     CASE WHEN delta_type = 'I' AND c.l2_no IS NULL THEN mk2 + ROW_NUMBER () OVER (ORDER BY delta_type) ELSE c.l2_key END AS new1_key, 
     CASE WHEN delta_type = 'I' AND d.l3_no IS NULL THEN mk3 + ROW_NUMBER () OVER (ORDER BY delta_type) ELSE d.l3_key END AS new1_key, 
     delta_type 
FROM   stg1 a 
LEFT OUTER JOIN lookup b ON a.x1 = b.x1 AND a.h_id = b.h_id AND a.l1_no = b.l1_no 
LEFT OUTER JOIN lookup c ON a.x1 = c.x1 AND a.h_id = c.h_id AND a.l1_no = c.l1_no AND a.l2_no = c.l2_no   
LEFT OUTER JOIN lookup d ON a.x1 = d.x1 AND a.h_id = d.h_id AND a.l1_no = d.l1_no AND a.l2_no = d.l2_no AND a.l3_no = d.l3_no 
LEFT OUTER JOIN dwh_keys xx ON a.x1 = xx.x1 AND a.h_id = xx.h_id; 

輸出我得到的（我想還什麼）

X1 H_ID L1_NO L2_NO L3_NO DELTA_TYPE NEW1_KEY NEW1_KEY NEW1_KEY DELTA_TYPE 
20 1 6 16 42 I 105 115 145 I 
20 1 5 15 41 I 106 116 146 I 
20 1 1 19 41 I 101 117 147 I 
20 1 2 12 42 U 102 112 142 U 

我的數據庫WX2犯規支持遞歸CTE和所有我擁有的是普通的ANSI SQL語法除了遞歸CTE一起玩。

Answer 1

終於找到了解決方案，但我最初建議的修改版本

WITH lookup (x1, h_id, l1_no, l1_key, l2_no, l2_key, l3_no, l3_key) AS 
     (SELECT 20, 1, 1, 101, 11, 111, 41, 141 FROM sys.DUAL UNION ALL 
      SELECT 20, 1, 1, 101, 12, 112, 42, 142 FROM sys.DUAL UNION ALL 
      SELECT 20, 1, 3, 102, 13, 113, 43, 143 FROM sys.DUAL UNION ALL 
      SELECT 20, 1, 4, 103, 14, 114, 44, 144 FROM sys.DUAL), 
    dwh_keys AS 
     (SELECT  x1, h_id, MAX (l1_key) mk1, MAX (l2_key) mk2, MAX (l3_key) mk3 
      FROM  lookup 
      GROUP BY 1, 2), 
    src (x1, h_id, l1_no, l2_no, l3_no) AS 
     (SELECT 20, 1, 1, 19, 41 FROM sys.DUAL UNION ALL 
      SELECT 20, 1, 1, 12, 42 FROM sys.DUAL UNION ALL 
      SELECT 20, 1, 5, 15, 41 FROM sys.DUAL UNION ALL 
      SELECT 20, 1, 6, 16, 42 FROM sys.DUAL), 
    stg1 AS 
     (SELECT DISTINCT b.*, CASE WHEN a.x1 IS NOT NULL THEN 'U' ELSE 'I' END AS delta_type 
      FROM  src b 
        LEFT OUTER JOIN 
        lookup a 
         ON  a.x1 = b.x1 
          AND a.h_id = b.h_id 
          AND a.l1_no = b.l1_no 
          AND a.l2_no = b.l2_no 
          AND a.l3_no = b.l3_no), 
    stg2 AS 
     (SELECT a.*, CASE WHEN delta_type = 'I' AND b.l1_no IS NULL THEN 0 ELSE 1 END AS flag1, b.l1_key AS k1, 
        CASE WHEN delta_type = 'I' AND c.l2_no IS NULL THEN 0 ELSE 1 END AS flag2, c.l2_key AS k2, 
        CASE WHEN delta_type = 'I' AND d.l3_no IS NULL THEN 0 ELSE 1 END AS flag3, d.l3_key AS k3 
      FROM  stg1 a 
        LEFT OUTER JOIN (SELECT DISTINCT x1, h_id, l1_no, l1_key FROM lookup) b 
         ON a.x1 = b.x1 AND a.h_id = b.h_id AND a.l1_no = b.l1_no 
        LEFT OUTER JOIN (SELECT DISTINCT x1, h_id, l1_no, l1_key, l2_no, l2_key FROM lookup) c 
         ON a.x1 = c.x1 AND a.h_id = c.h_id AND a.l1_no = c.l1_no AND a.l2_no = c.l2_no 
        LEFT OUTER JOIN 
        (SELECT DISTINCT x1, h_id, l1_no, l1_key, l2_no, l2_key, l3_no, l3_key FROM lookup) d 
         ON  a.x1 = d.x1 
          AND a.h_id = d.h_id 
          AND a.l1_no = d.l1_no 
          AND a.l2_no = d.l2_no 
          AND a.l3_no = d.l3_no), 
    keys AS 
     (SELECT a.*, 
        CASE WHEN flag1 = 0 THEN mk1 + DENSE_RANK () OVER (ORDER BY a.delta_type, l1_no) ELSE a.k1 END AS new_key1, 
        CASE WHEN flag2 = 0 THEN mk2 + DENSE_RANK () OVER (ORDER BY a.delta_type, l1_no, l2_no) ELSE a.k2 END AS new_key2, 
        CASE WHEN flag3 = 0 THEN mk3 + DENSE_RANK () OVER (ORDER BY a.delta_type, l1_no, l2_no, l3_no) ELSE a.k3 END AS new_key3 
      FROM  stg2 a LEFT OUTER JOIN dwh_keys b ON a.x1 = b.x1 AND a.h_id = b.h_id) 
SELECT  x1, h_id, l1_no, l2_no, l3_no, delta_type, new_key1, new_key2, new_key3 
FROM  keys 
ORDER BY 1, 2, 3, 4, 5;