-2
我有一個多維數組如下重新排列數組索引
Array
(
[0] => attributewidget Object
(
[_child] => Array
(
)
[_parent] =>
[_oid] => a_1
[_errorMsg] =>
[_debugTraceFunc] =>
[classname] => AttributeWidget
[version] => 1.0.0.0
[attributeName] =>
[comparableProperties] => Array
(
[0] => abbreviation
[1] => attributeName
[2] => classname
[3] => conditionRef
)
)
[1] => Array
(
[0] => attributewidget Object
(
[_child] => Array
(
)
[_parent] =>
[_oid] => a_2
[_errorMsg] =>
[_debugTraceFunc] =>
[classname] => AttributeWidget
[version] => 1.0.0.0
[attributeName] =>
[comparableProperties] => Array
(
[0] => abbreviation
[1] => attributeName
[2] => classname
[3] => conditionRef
)
)
)
[2] => Array
(
[0] => attributewidget Object
(
[_child] => Array
(
)
[_parent] =>
[_oid] => a_3
[_errorMsg] =>
[_debugTraceFunc] =>
[classname] => AttributeWidget
[version] => 1.0.0.0
[attributeName] => cp1
[comparableProperties] => Array
(
[0] => abbreviation
[1] => attributeName
[2] => classname
[3] => conditionRef
)
)
)
)
我理想想刪除[1] =>數組[2] =>數組和重新排列的索引。 有沒有一種方法可以讓索引重新排列如下。
Array
(
[0] => attributewidget Object
(
[_child] => Array
(
)
[_parent] =>
[_oid] => a_1
[_errorMsg] =>
[_debugTraceFunc] =>
[classname] => AttributeWidget
[version] => 1.0.0.0
[attributeName] =>
[comparableProperties] => Array
(
[0] => abbreviation
[1] => attributeName
[2] => classname
[3] => conditionRef
)
)
[1] => attributewidget Object
(
[_child] => Array
(
)
[_parent] =>
[_oid] => a_2
[_errorMsg] =>
[_debugTraceFunc] =>
[classname] => AttributeWidget
[version] => 1.0.0.0
[attributeName] => Name?
[comparableProperties] => Array
(
[0] => abbreviation
[1] => attributeName
[2] => classname
[3] => conditionRef
)
)
[2] => attributewidget Object
(
[_child] => Array
(
)
[_parent] =>
[_oid] => a_3
[_errorMsg] =>
[_debugTraceFunc] =>
[classname] => AttributeWidget
[version] => 1.0.0.0
[attributeName] => cp1
[comparableProperties] => Array
(
[0] => abbreviation
[1] => attributeName
[2] => classname
[3] => conditionRef
)
)
)
這個數組是如何創建得如此不一致?爲什麼'[0]'直接指向一個對象,但是'[1]'和'[2]'中有一個額外的數組?也許你應該修復創建數組的代碼,所以它不會這樣做。 – Barmar
臨發佈提示:[避免請求志願者緊急](http://meta.stackoverflow.com/q/326569)。 – halfer