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我有一個簡短的測試程序來獲取本地機器的IP地址。在Raspbian上,僅返回回送地址,而OS X上的相同代碼返回正常IP和回送IP。在raspbian上的getaddrinfo只返回loopback IP,在OS X上有相同的代碼
的代碼是
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
#include <iostream>
#include <sys/types.h>
#include <sys/socket.h>
#include <netdb.h>
#include <arpa/inet.h>
#include <errno.h>
using namespace std;
int main (int argc, char * const argv[]) {
char hostname[128];
int result = gethostname(hostname, 127);
if (result != 0) {
cout << "FATAL: gethostname failed: " << result << errno;
return -1;
}
cout << "Host name is " << hostname << endl;
struct addrinfo hints, *res;
int errcode;
char addrstr[100];
void *ptr;
memset(&hints, 0, sizeof(hints));
hints.ai_family = PF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_flags |= AI_CANONNAME;
errcode = getaddrinfo(hostname, NULL, &hints, &res);
if (errcode != 0) {
perror("getaddrinfo");
return -1;
}
while(res) {
inet_ntop(res->ai_family, res->ai_addr->sa_data, addrstr, 100);
switch(res->ai_family) {
case AF_INET:
ptr = &((struct sockaddr_in *)res->ai_addr)->sin_addr;
break;
case AF_INET6:
ptr = &((struct sockaddr_in6 *)res->ai_addr)->sin6_addr;
break;
default:
cout << "Unknown family" << endl;
}
inet_ntop(res->ai_family, ptr, addrstr, 100);
printf("IPV%d address: %s (%s)\n", res->ai_family == PF_INET6 ? 6 : 4, addrstr, res->ai_canonname);
res = res->ai_next;
}
return 0;
}
在OS X上我得到:
[Coyote]collector$ ./quick
Host name is Coyote.local
IPV4 address: 192.168.1.108 (coyote.local)
IPV6 address: fe80::223:dfff:fea0:a230 (coyote.local)
但在Raspbian我只得到:
pi:~$ ./quick
Host name is pi
IPV4 address: 127.0.1.1 (pi)
但
pi:~$ ifconfig
eth0 Link encap:Ethernet HWaddr b8:27:eb:62:15:fc
inet addr:192.168.1.162 Bcast:192.168.1.255 Mask:255.255.255.0
[...]
我需要做Raspbian才能獲得正確結果?
謝謝。這工作。 – RussK
有趣的一面是:我實際上需要Ruby on Rails應用程序中的這些信息。經過痛苦的工作之後,我不得不通過Ruby來使getifaddrs可用,我想,沒有什麼期望,去尋找一個Ruby gem。令我驚訝的是,我找到了[system-getifaddrs](https://rubygems.org/gems/system-getifaddrs)gem,它以散列形式返回結果,其中接口是鍵,值是散列值。尼斯。 – RussK