2011-09-14 172 views
6

誰能幫助我弄清楚,爲什麼我得到一個錯誤的cms.CRIME_ID奇怪的Oracle SQL「無效的」錯誤

invalid identifier

select c.criminal_id, c.first, c.last, cms.CRIME_ID, cc.crime_code, cc.fine_amount 
from criminals c join crimes cms on c.criminal_id = cms.criminal_id 
join crime_charges cc using (crime_id) 
order by c.first, c.last; 

我知道絕對的事實,列存在,我可以引用所有其他除此之外,該表中的列。

與該列唯一不同的是它是該表的主鍵。

編輯:這是完整的錯誤和表創建腳本。

Error starting at line 1 in command: 
select c.criminal_id, c.first, c.last, cms.CRIME_ID, cc.crime_code, cc.fine_amount 
from criminals c join crimes cms on c.criminal_id = cms.criminal_id 
join crime_charges cc using (crime_id) 
order by c.first, c.last 
Error at Command Line:1 Column:39 
Error report: 
SQL Error: ORA-00904: "CMS"."CRIME_ID": invalid identifier 
00904. 00000 - "%s: invalid identifier" 
*Cause:  
*Action: 

CREATE TABLE crimes 
     (crime_id NUMBER(9), 
     criminal_id NUMBER(6), 
     classification CHAR(1), 
     date_charged DATE, 
     status CHAR(2), 
     hearing_date DATE, 
     appeal_cut_date DATE); 

ALTER TABLE crimes 
    MODIFY (classification DEFAULT 'U'); 
ALTER TABLE crimes 
    ADD (date_recorded DATE DEFAULT SYSDATE); 
ALTER TABLE crimes 
    MODIFY (criminal_id NOT NULL); 
ALTER TABLE crimes 
    ADD CONSTRAINT crimes_id_pk PRIMARY KEY (crime_id); 
ALTER TABLE crimes 
    ADD CONSTRAINT crimes_class_ck CHECK (classification IN('F','M','O','U')); 
ALTER TABLE crimes 
    ADD CONSTRAINT crimes_status_ck CHECK (status IN('CL','CA','IA')); 
ALTER TABLE crimes 
    ADD CONSTRAINT crimes_criminalid_fk FOREIGN KEY (criminal_id) 
      REFERENCES criminals(criminal_id); 
ALTER TABLE crimes 
    MODIFY (criminal_id NOT NULL); 

EDIT2:另外,我也許應該提到的是不使用的時候加入,只是普通的SELECT語句,我可以訪問列就好了,如下面的代碼示例:

select c.criminal_id, c.first, c.last, cms.crime_id, cc.crime_code, cc.fine_amount 
from criminals c, crime_charges cc, crimes cms 
where c.criminal_id = cms.criminal_id 
and cms.crime_id = cc.crime_id 
order by c.first, c.last; 
+0

請發表 –

+1

請問您的用戶所涉及的表的詳細信息,對所犯罪行表的權限? –

+0

什麼是crime_charges表的定義? – Ollie

回答

0

你試過以下嗎?

Join On (Left Id) = (Right Id) 

相反關鍵字Using

+0

是的,不幸的是,這並沒有幫助。 – JohnQPublic

+0

加入使用()vs Join On()=()是相同的。 – Thinhbk

0

試,使一個別名加入語句子句:

select alias.criminal_id, alias.first, alias.last, alias.CRIME_ID, alias.crime_code, alias.fine_amount 
from criminals c join crimes cms on c.criminal_id = cms.criminal_id 
join crime_charges cc using (crime_id) as alias 
order by alias.first, alias.last; 
1

不能使用限定詞與「使用」引用的列clause.you可以使用內部聯接代替 嘗試使用此查詢:

select c.criminal_id, c.first, c.last, cms.CRIME_ID, cc.crime_code, cc.fine_amount 
from criminals c join crimes cms on c.criminal_id = cms.criminal_id 
join crime_charges cc on cc.crime_id=cms.crime_id 
order by c.first, c.last; 
3

這裏的問題是,當您的查詢有USING子句時,您無法向本子句中使用的列添加限定符。因爲您的查詢有USING (crime_id),您不能寫cms.CRIME_IDcc.crime_id。相反,您必須刪除限定符,即只使用crime_id

奇怪的是,當我嘗試這個上的Oracle 11g XE測試版,我得到一個不同的錯誤:

 
SQL> select * from test1; 

     A   B 
---------- ---------- 
     1   2 

SQL> select * from test2; 

     A   C 
---------- ---------- 
     1   3 

SQL> select t1.a, t1.b, t2.c from test1 t1 inner join test2 t2 using (a); 
select t1.a, t1.b, t2.c from test1 t1 inner join test2 t2 using (a) 
     * 
ERROR at line 1: 
ORA-25154: column part of USING clause cannot have qualifier 


SQL> select a, t1.b, t2.c from test1 t1 inner join test2 t2 using (a); 

     A   B   C 
---------- ---------- ---------- 
     1   2   3