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我寫了下面的SQL語句,在測試表,我有4個記錄,並對coa_body表我也有四個記錄,這個查詢:MySQL來返回獨特的記錄
SELECT `name`, `compedia`, `specification`
FROM (`tests` t, `coa_body` cb)
JOIN
`request_details` rd
ON `t`.`id` = `rd`.`test_id`
WHERE `rd`.`request_id` = 'NDQA201303001' AND cb.labref = 'NDQA201303001';
回報:
1.name compedia說明書
Assay Alphy poxy
pH(Acidity/Alkalinity) Alphy poxy
Sterility Alphy poxy
Bacterial Endotoxin Test Alphy poxy
Assay poxy alphy
pH(Acidity/Alkalinity) poxy alphy
Sterility poxy alphy
Bacterial Endotoxin Test poxy alphy
Assay alphy1 poxy1
pH(Acidity/Alkalinity) alphy1 poxy1
Sterility alphy1 poxy1
Bacterial Endotoxin Test alphy1 poxy1
Assay poxy1 alphy1
pH(Acidity/Alkalinity) poxy1 alphy1
Sterility poxy1 alphy1
Bacterial Endotoxin Test poxy1 alphy1
2.coa_body表如下: ID labref compedia規範
1 NDQA201303001 Alphy poxy
2 NDQA201303001 poxy alphy
3 NDQA201303001 alphy1 poxy1
4 NDQA201303001 poxy1 alphy1
3.我只需要4條一模一樣這樣
name compedia specification
Assay Alphy poxy
pH(Acidity/Alkalinity) poxy alphy
Sterility alphy1 poxy1
Bacterial Endotoxin Test poxy1 alphy1
4.at查詢結束的coa_body表,如果我添加GROUP BY t.name語句,它返回
name compedia specification
Assay Alphy poxy
Bacterial Endotoxin Test Alphy poxy
pH(Acidity/Alkalinity) Alphy poxy
Sterility Alphy poxy
這是不是想讓我想要的,我想要的結果是一個在3號
請不要使用不適用於您的問題的標籤 –
好的,下次再記住這一點 – alphy