不能提取正則表達式的子字符串

Question

我想爲git寫一個prepare-commit-msg鉤子。該腳本應該做以下步驟：

1. 獲取當前的git分支名（工作）
2. 提取issue-id（不工作）
3. 檢查是否issue-id已經在提交味精
4. 如果沒有插入[issue-id]提交信息前

的issue-id了這種模式[a-zA-Z]+-\d+和分支的名稱應該是舒美特像feature/issue-id-my-small-description一樣興奮。

但現在，提取的部分是不正常...

這是我準備提交 - 味精腳本：

# Regex used to extract the issue id 
REGEX_ISSUE_ID="s/([a-zA-Z]+-\d+)//" 

# Find current branch name 
BRANCH_NAME=$(git symbolic-ref --short HEAD) 

# Extract issue id from branch name 
ISSUE_ID= $BRANCH_NAME | sed -r $REGEX_ISSUE_ID 

# Check if the issue id is already in the msg 
ISSUE_IN_COMMIT=$(grep -c "\[$ISSUE_ID\]" $1) 

# Check if branch name is not null and if the issue id is already in the commit msg 
if [ -n "$BRANCH_NAME" ] && ! [[ $ISSUE_IN_COMMIT -ge 1 ]]; then 
    # Prefix with the issue id surrounded with brackets 
    sed -i.bak -e "1s/^/[$ISSUE_ID] /" $1 
fi 

編輯添加輸入/輸出例如

輸入$1是git commit消息，類似於

fix bug on login 

或

fix MyIssue-234 which is a bug on login 

輸出應該是這個問題的ID即輸入：

[MyIssue-123] fix bug on login 

Answer 1

我不知道什麼以及爲什麼這樣做，你做什麼，但是這是最接近我通過固定我的想法得到了在你的代碼加以糾正：

# Regex used to extract the issue id 
REGEX_ISSUE_ID="s/\[([a-zA-Z]+-[0-9]+)\].*/\1/" 

# Find current branch name 
BRANCH_NAME=$(git symbolic-ref --short HEAD) 
if [[ -z "$BRANCH_NAME" ]]; then 
    echo "No brach name... "; exit 1 
fi 

# Extract issue id from branch name 
ISSUE_ID=$(echo "$BRANCH_NAME" | sed -r "$REGEX_ISSUE_ID") 

# Check if the issue id is already in the msg 
ISSUE_IN_COMMIT=$(echo "$@" | grep -c "^\[*$ISSUE_ID\]*") 

# Check if branch name is not null and if the issue id is already in the commit msg 
if [[ -n "$BRANCH_NAME" ]]; then 
    if [[ $ISSUE_IN_COMMIT -gt 0 ]]; then 
     shift # Drop the issue if from the msg 
    fi 
    # Prefix with the issue id surrounded with brackets 
    MESSAGE="[$ISSUE_ID] $@" 
fi 

echo "$MESSAGE" 

其中$@是所有你之後「修理」（如提供的話。 "$@" = "bug" "on" "login"）。其餘的我希望你在把它與你的原始代碼進行比較後能夠理解。