分割字符串每個字符發生

Question

SSMS字符2016企業

如果我有以下弦一柱：

$/Harmony/Maintenance/6.0/Dev/ 

如何創建以下結果

Column1 | Column 2 | Column 3 | Column 4 | Column 5 

    $  Harmony Maintenance 6.0   Dev 

字符串中的最大數字/將爲27.因此，在每一行中，/的數目可以它們之間的字符串也不盡相同。

我需要創建27列並填充它們，如果字符串只有5，那麼下面的表將是空的。

我嘗試了使用CHARINDEX和SUBSTRING的解決方案，但我無法按照我目前的要求使其工作。

謝謝你們！

Answer 1

它requiers一些編碼，但我的總體思路是：

創建動態地查詢，然後執行它。

我提供了可以應用的解決方案。我基於固定字符串（您提供的），將它分配給@str變量並對其進行修改。但是你可以把它放在一個循環中，在循環的每一次運行中你都可以給它賦一個新的字符串，這個字符串將以一種給定的方式進行轉換。每次循環執行後，都會運行插入查詢。

create table #resultTable(
col1 varchar(50), col2 varchar(50), col3 varchar(50), col4 varchar(50), col5 varchar(50), col6 varchar(50), col7 varchar(50), 
col8 varchar(50), col9 varchar(50), col10 varchar(50), col11 varchar(50), col12 varchar(50), col13 varchar(50), col14 varchar(50), 
col15 varchar(50), col16 varchar(50), col17 varchar(50), col18 varchar(50), col19 varchar(50), col20 varchar(50), col21 varchar(50), 
col22 varchar(50), col23 varchar(50), col24 varchar(50), col25 varchar(50), col26 varchar(50), col27 varchar(50) 
) 

declare @tableToSplit table(id int identity(1,1), ColumnWithStringToSplit varchar(2000)) 
insert into @tableToSplit values ('$/Harmony/Maintenance/6.0/Dev/'), 
('$/Harmony/Maintenance/6.0/Dev/123/'),('$/Harmony/Maintenance/6.0/Dev/123/456/') 
select * from @tableToSplit 

declare @howManyRows int, @id int, @iterator int = 1 
select @howManyRows = count(*) from @tableToSplit 

declare @i int, @counter int, @values varchar(1000), @query nvarchar(2000) 

while @iterator <= @howManyRows 
begin 
    set @query = 'insert into #resultTable (' 
    --get values from table 
    select top 1 @id = id, @values = ColumnWithStringToSplit from 
    @tableToSplit 
    --count how many strings we will have, which is equal to number of '/' in string 
    set @i = len(@values) - len(replace(@values,'/','')) 
    --get rid of last forward-slash 
    set @values = left(@values, len(@values) - 1) 
    --replace all slashes, so it can be used as part of insert statement 
    set @values = '(''' + REPLACE(@values, '/', ''',''') + ''')' 

    set @counter = 1 
    while @counter <= @i 
    begin 
     set @query = @query + 'col' + cast(@counter as varchar(2)) + ',' 

     set @counter = @counter + 1 
    end 
    --get rid of last comma and append rest of the query 
    set @query = left(@query, len(@query) - 1) + ') values ' + @values 

    exec sp_executesql @query 
    --we processed that row, so we need to delete it 
    delete from @tableToSplit where id = @id 
    set @iterator = @iterator + 1 
end 

select * from #resultTable 

這裏有一個結果（有第27欄，如果你想知道）的畫面：

Answer 2

我會首先創建一個函數來分割您的字符串，然後在之後進行轉換。

功能：

CREATE FUNCTION [dbo].[dba_parseString_udf] (
     @stringToParse VARCHAR(8000) 
    , @delimiter  CHAR(1) 
) 
RETURNS @parsedString TABLE (stringValue VARCHAR(128)) AS 
BEGIN 

/* Declare variables */ 
DECLARE @trimmedString VARCHAR(8000); 

/* We need to trim our string input in case the user entered extra spaces */ 
SET @trimmedString = LTRIM(RTRIM(@stringToParse)); 

/* Let's create a recursive CTE to break down our string for us */ 
WITH parseCTE (StartPos, EndPos) 
AS 
(
    SELECT 1 AS StartPos 
     , CHARINDEX(@delimiter, @trimmedString + @delimiter) AS EndPos 
    UNION ALL 
    SELECT EndPos + 1 AS StartPos 
     , CHARINDEX(@delimiter, @trimmedString + @delimiter , EndPos + 1) AS EndPos 
    FROM parseCTE 
    WHERE CHARINDEX(@delimiter, @trimmedString + @delimiter, EndPos + 1) <> 0 
) 

/* Let's take the results and stick it in a table */ 
INSERT INTO @parsedString 
SELECT SUBSTRING(@trimmedString, StartPos, EndPos - StartPos) 
FROM parseCTE 
WHERE LEN(LTRIM(RTRIM(SUBSTRING(@trimmedString, StartPos, EndPos - StartPos)))) > 0 
OPTION (MaxRecursion 8000); 

RETURN; 
END 

在此之後，我會轉動結果：

----For test purpose----- 
DECLARE @Table TABLE (
ID int null, 
string nvarchar(500) null 
) 

INSERT into @Table (ID,String) 
VALUES(1,'$/Harmony/Maintenance/6.0/Dev/'), 
(2,'$/Harmony/Maintenance/6.0/Dev/Test/') 
-------------------------- 



select [Column1],[Column2],[Column3],[Column4],[Column5],[Column6], 
[Column7],[Column8],[Column9],[Column10],[Column11],[Column12],[Column13] 
,[Column14],[Column15],[Column16],[Column17],[Column18],[Column19], 
[Column20],[Column21],[Column22],[Column23],[Column24],[Column25], 
[Column26],[Column27] 
FROM 
(
SELECT 'Column' + cast(Row_number() over(Partition BY ID order by ID) as 
varchar(50)) as ColumnRow, 
* FROM @Table 
CROSS APPLY dbo.[dba_parseString_udf](string,'/') 
) AS SOURCETABLE 
PIVOT 
(
min(stringValue) 
FOR ColumnRow IN ([Column1],[Column2],[Column3],[Column4],[Column5], 
[Column6],[Column7],[Column8],[Column9],[Column10],[Column11],[Column12], 
[Column13] 
,[Column14],[Column15],[Column16],[Column17],[Column18],[Column19], 
[Column20],[Column21],[Column22],[Column23],[Column24],[Column25], 
[Column26],[Column27]) 
) 
AS 
PivotTable 

Answer 3

然而，在演唱會使用一些XML的另一種選擇帶有CROSS APPLY。

易於擴展到27 ...該模式是很簡單

EDIT - 增加2ndToLast - 還增加NULLIF（），其是可選的

例

Select B.* 
     ,[2ndToLast] = reverse(Cast('<x>' + replace((Select replace(reverse(A.SomeCol),'/','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).value('/x[3]','varchar(max)')) 
From @YourTable A 
Cross Apply (
       Select Pos1 = nullif(xDim.value('/x[1]','varchar(max)'),'') 
         ,Pos2 = nullif(xDim.value('/x[2]','varchar(max)'),'') 
         ,Pos3 = nullif(xDim.value('/x[3]','varchar(max)'),'') 
         ,Pos4 = nullif(xDim.value('/x[4]','varchar(max)'),'') 
         ,Pos5 = nullif(xDim.value('/x[5]','varchar(max)'),'') 
         ,Pos6 = nullif(xDim.value('/x[6]','varchar(max)'),'') 
         ,Pos7 = nullif(xDim.value('/x[7]','varchar(max)'),'') 
         ,Pos8 = nullif(xDim.value('/x[8]','varchar(max)'),'') 
         ,Pos9 = nullif(xDim.value('/x[9]','varchar(max)'),'') 
       From (Select Cast('<x>' + replace((Select replace(A.SomeCol,'/','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as A 
      ) B 

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