如何使用查詢功能在Drupal

Question

如何編寫SQL查詢功能在Drupal，

SELECT title FROM { node } WHERE type='%s' 

我想補充LIKE條件在

SELECT title FROM { node } WHERE type='%s' AND LIKE '%S%' 

我想我writtern錯像查詢formnat ，可以重寫並告訴我，

Answer 1

只需使用％逃脫。

$result = db_query('SELECT title FROM {node} WHERE type = "%s" AND title LIKE "%%%s%%"', 'type', 'title'); 

while ($row = db_fetch_object($result)) { 
    // do stuff with the data 
} 

節點類型不需要轉義。

Answer 2

好吧，所以你想LIKE運營商參考title列。使用此查詢：

$sql = "SELECT title FROM node WHERE type='%s' AND title LIKE '%S%'"; 
$type = "type to use in query"; 
$title = "title to use in query";  
$result = db_result(db_query($sql, $type, $title)); 

這是因爲LIKE操作符需要指定列名稱。否則，您的數據庫不知道您想要執行比較的值。見here。

Answer 3

drupal_query替換%%到％和％s到字符串值

所以你的代碼會

$sql = "SELECT title FROM node WHERE type='%%%s' AND title LIKE '%%%S%%'"; 
$type = "type to use in query"; 
$title = "title to use in query";  
$result = db_result(db_query($sql, $type, $title)); 

Answer 4

這裏是如何在一個動態查詢（Drupal的7只）LIKE用一個例子：

$query = db_select('node', 'n') 
     ->fields('n', array('title')) 
     ->condition('type', 'my_type') 
     ->condition('title', '%' . db_like(search_string) . '%', 'LIKE'); 
    $result = $query->execute()->fetchCol(); 

db_like()用來逃脫，在LIKE模式工作作爲通配符的字符。