slice_mut for＆mut [T]

Question

爲什麼MutableSlice::slice_mut未執行& mut [T]？

測試在rustc 0.12.0-夜間（b2d4eb186 2014年10月2日15時57分19秒0000）：

fn sort<T>(v: &mut [T]){ 
    let (l, r) = v.split_at_mut(2); // Ok 
    let len = v.slice_mut(1u, 3u).len(); // error: type `&mut [T]` does not implement any method in scope named `slice_mut` 
} 

#[test] 
fn it_works() { 
    let mut v = [1i, 2, 3, 4, 5, 6]; 
    sort(v); 
} 

Answer 1

也就是說方法had been removed，但the change has since been rolled back。您的sort函數compiles right now的第二行。