轉換Json的字典對象到Python dicitonary

Question

我有一個JSON文件與字典一樣的物體

{"d1a": 91, "d1b": 2, "d1c": 1, "d1d": 5, "d1e": 7, "d1f": 77, "d1e": 999} 
{"d2a": 1, "d2b": 2, "d2c": 3, "d2d": 4, "d2e": 5, "d2f": 6, "d2e": 7} 
{"d3a": 1, "d3b": 2, "d3c": 3, "d3d": 4, "d3e": 5, "d3f": 6, "d3e": 7} 

我打算將它轉換成一個Python字典格式相同

with open(myfile.json, 'r') as myfile: 
# not sure how the conversion will start 

Answer 1

如果這是怎麼了文件內容看起來像，它不是一個有效的JSON作爲一個整體，但每一行都是。

您可以通過線讀取文件線路和呼叫json.loads()：

import json 

with open(myfile.json, 'r') as myfile: 
    for line in myfile: 
     print(json.loads(line)) 

而且你可以有一個字典列表，如果你會使用list comprehension：

objs = [json.loads(line) for line in myfile] 

你也可以如果您將[和]包含在內容中並在每行末尾加上逗號，請撥打loads()一次：

with open("test.json") as myfile: 
    data = "[" + ",".join(myfile.readlines()) + "]" 
    print(json.loads(data)) 

Answer 2

如果你還沒有，你需要

import json 

然後，

with open(myfile.json, 'r') as file: 
    data = json.load(file) 

而且，你有沒有包含有效的JSON。你可以用你所擁有的在一個數組，使其正常解析：

[ 
    {"d1a": 91, "d1b": 2, "d1c": 1, "d1d": 5, "d1e": 7, "d1f": 77, "d1e": 999}, 
    {"d2a": 1, "d2b": 2, "d2c": 3, "d2d": 4, "d2e": 5, "d2f": 6, "d2e": 7}, 
    {"d3a": 1, "d3b": 2, "d3c": 3, "d3d": 4, "d3e": 5, "d3f": 6, "d3e": 7} 
]