針對團隊計劃的MySQL查詢

我想根據下表獲取每個團隊的計劃，但我在獲取團隊名稱時顯示出一些問題。這裏是我的表：針對團隊計劃的MySQL查詢

TEAM （TEAM_ID， TEAM_NAME， team_mascot，等）

GAME （game_id， GAME_DATE， game_home_team， game_visitor_team， game_home_score， game_visitor_score， game_complete ）

這是我目前的查詢。我能夠通過這個獲得團隊的id值，但是我需要團隊名稱，因爲id值對我來說不會有太大幫助。

SELECT game_home_team, game_visitor_team, game_date 
FROM game 
INNER JOIN team home ON home.team_id = game_home_team 
INNER JOIN team visitor ON visitor.team_id = game_visitor_team 
WHERE game_home_team = ? 
OR game_visitor_team = 6 
ORDER BY game_date ASC;

我怎麼能與此查詢檢索的隊名也顯示結果如W或L視得分爲遊戲？非常感謝提前。

來源

2012-07-17 WebDev84

哪支球隊你想賣，遊客或家庭的W和L？ – DrinkJavaCodeJava 2012-07-17 18:29:37

SELECT 
    home.team_name AS home_team, 
    visitor.team_name AS visitor_team, 
    game_date, 
    IF(
     game_home_score = game_visitor_score, 
     'Tie', 
     IF(
     game_home_score > game_visitor_score, 
     'Hometeam', 
     'Visitorteam' 
    ) 
    ) AS Winner 
FROM game 
INNER JOIN team home ON home.team_id = game_home_team 
INNER JOIN team visitor ON visitor.team_id = game_visitor_team 
WHERE game_home_team = ? 
OR game_visitor_team = 6 
ORDER BY game_date ASC;

來源

2012-07-17 18:27:22

感謝您的快速回復。我現在面臨的問題是home_team和visitor_team都顯示爲相同。 – WebDev84 2012-07-17 18:37:56

沒關係，我明白了。謝謝！ – WebDev84 2012-07-17 18:56:43

@ RCM8402如果你對SO的回答感到滿意，你應該[接受]（http://meta.stackexchange.com/questions/5234/how-does-accepting-an-answer-work）回答，看看你迄今未接受任何答案 – 2012-07-17 20:22:21

select game_home_team, home.team_name AS homename, 
    game_visitor_team, visitor.team_name AS visitorname 
etc...

來源

2012-07-17 18:27:54

針對團隊計劃的MySQL查詢

回答

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