我有這種奇怪的情況,我第一次遇到,並給予我在PHP中的新地位,它更令人困惑。在下面的查詢中,「請求者」這個詞重複的次數比它應該多。它重複的次數與它猜想的假設數量有關。如何防止在「回聲」命令中重複出現的單詞?
代碼:
$sql = "SELECT DISTINCT
allowed_permissions.post_id,
client_visit.client_reason,
accounts.full_name,
client_visit.type
from allowed_permissions
LEFT JOIN
client_visit
on allowed_permissions.post_id = client_visit.visit_id
LEFT JOIN
accounts
ON client_visit.system_id = accounts.system_id
where
allowed_permissions.allowed_to_view = '$uid'";
$result = mysql_query($sql);
$query = mysql_query($sql) or die ("Error: ".mysql_error());
if ($result == "") {
echo "";
}
echo "";
$rows = mysql_num_rows($result);
if($rows == 0) {
} elseif($rows > 0) {
while($row = mysql_fetch_assoc($query)) {
$reason = $row['client_reason'];
$person = $row['full_name'];
//Here the asked word gets repeated...
echo"$reason asked by $person";
}
}
你在while循環中有「問」這個詞,那麼問題是什麼? – Anas
向我們顯示您的輸出和您的預期輸出。當你在mysql中運行查詢時,它是否會產生預期的結果? – Jrod
看到,distinct將不會返回不同的'client_reason,full_name'集合,而是它將返回查詢 – Imdad