我有這個2個SELECT語句充分利用2條SELECT語句,其返回多行
SELECT SizeName,SUM(DESIGNSIZERELEASE.Quantity) as [Release]
FROM DESIGNRELEASE JOIN
DESIGNSIZERELEASE
ON DESIGNRELEASE.DesignReleaseID = DESIGNSIZERELEASE.DesignReleaseID JOIN
SIZESET
ON SIZESET.SizeSetID = DESIGNSIZERELEASE.SizeSetID AND
DESIGNRELEASE.RevisionNo = SIZESET.RevisionNo
WHERE DESIGNRELEASE.RevisionNo = 2 AND DESIGNRELEASE.DesignID='SD00000'
GROUP BY DESIGNRELEASE.DesignID,Towhom,SizeName
ORDER BY case SizeName when 'XS' then 1 when 'S' then 2 when 'M' then 3 when 'L' then 4 when 'XL' then 5 end
和
SELECT SUM(DESIGNRECEIVEDETAILS.Quantity) as [Receive]
FROM DESIGNRELEASE JOIN
DESIGNSIZERELEASE
ON DESIGNRELEASE.DesignReleaseID = DESIGNSIZERELEASE.DesignReleaseID JOIN
SIZESET
ON SIZESET.SizeSetID = DESIGNSIZERELEASE.SizeSetID AND
DESIGNRELEASE.RevisionNo = SIZESET.RevisionNo JOIN
DESIGNRECEIVE
ON DESIGNRECEIVE.DesignReleaseID = DESIGNRELEASE.DesignReleaseID JOIN
DESIGNRECEIVEDETAILS
ON DESIGNRECEIVE.ReceiptID = DESIGNRECEIVEDETAILS.ReceiptID AND
DESIGNRECEIVEDETAILS.SizeSetID = SIZESET.SizeSetID
WHERE DESIGNRELEASE.RevisionNo = 2 AND DESIGNRELEASE.DesignID='SD00000'
GROUP BY DESIGNRELEASE.DesignID,Towhom,SizeName
ORDER BY case SizeName when 'XS' then 1 when 'S' then 2 when 'M' then 3 when 'L' then 4 when 'XL' then 5 end
有這2個結果
+----------+-------------+
|Size NAME |RELEASE |
+----------+-------------+
|S |20 |
+----------+-------------+
|M |20 |
+----------+-------------+
+----------+
|Receive |
+----------+
|10 |
+----------+
|10 |
+----------+
我需要得到的差異發佈和接收的區別我該怎麼做?感謝順便說一句我分開他們,因爲我沒有得到正確的結果,當我把它們在一個單一的選擇聲明
您是否嘗試過在「Size Name」上加入表格,然後使用ABS(ColA-ColB)'找到絕對差異? –
@DanielPark還沒有試試 – Vince
@DanielPark它返回0 – Vince