MySQL組由與where子句計數大於1

Question

這應該是非常簡單我知道，但對於我的生活，我無法讓我的查詢做我需要的。

我在尋找找到所有屬於ref的特定狀態的行（paid），但僅限於找到多於1行的行。

這是我的示例表：

+-----+----------+----------+-------+ 
| id | deleted | status | ref | 
+-----+----------+----------+-------+ 
| 1 |  0 | pending | 10001 | 
| 2 |  0 | paid  | 10001 | 
| 3 |  0 | paid  | 10001 | 
| 4 |  0 | paid  | 10002 | 
| 5 |  1 | pending | 10002 | 
| 6 |  1 | paid  | 10002 | 
| 7 |  0 | pending | 10003 | 
| 8 |  0 | paid  | 10003 | 
| 9 |  0 | paid  | 10003 | 
| 10 |  0 | paid  | 10003 | 
| 11 |  0 | pending | 10004 | 
| 12 |  0 | paid  | 10004 | 
| 13 |  1 | pending | 10005 | 
| 14 |  1 | paid  | 10005 | 
| 15 |  1 | paid  | 10005 | 
| 16 |  0 | paid  | 10005 | 
| 17 |  0 | pending | 10006 | 
| 18 |  0 | paid  | 10006 | 
| 19 |  0 | paid  | 10006 | 
+-----+----------+----------+-------+ 

這是我的SQL：

SELECT * FROM `orders` 
WHERE `deleted` = 0 AND `status` = 'paid' 
GROUP BY SUBSTR(`ref`,0,5) 
HAVING COUNT(*) > 1 
ORDER BY `id` DESC 

我需要把它匹配的SUBSTR由於ref有時包含附加的數字。

的問題是，我的查詢返回這樣的：

+-----+----------+---------+-------+ 
| id | deleted | status | ref | 
+-----+----------+---------+-------+ 
| 2 |  0 | paid | 10001 | 
+-----+----------+---------+-------+ 

當我想它可以返回ref小號10001，10003 & 10006。

任何人都可以幫我弄清楚我做錯了什麼嗎？

感謝

Answer 1

嘗試

SELECT * FROM `orders` 
WHERE `deleted` = 0 AND `status` = 'paid' 
GROUP BY SUBSTR(`ref`,1,5) 
HAVING COUNT(*) > 1 
ORDER BY `id` DESC 

位置，論據SUBSTR從1開始，而不是0。

Answer 2

從SUBSTR DOC：

對於所有形式的子串（），要從中提取子串的字符串中的第一個字符的位置被認爲是1.

那麼試試這個：

SELECT * FROM `orders` 
WHERE `deleted` = 0 AND `status` = 'paid' 
GROUP BY SUBSTR(`ref`,1,5) 
HAVING COUNT(*) > 1 
ORDER BY `id` DESC