爲什麼我的提交表單將我帶到我的php頁面？

Question

（我沒有意識到我之前已經制作的貼子可以編輯並重新打開，對此過程感到困惑......）

當我點擊發送表單時，我發送到我的PHP頁面顯示數字0.我不明白爲什麼會發生這種情況。這裏的（大部分）全碼：

<form id="contactForm" method="post" action="js/formCheck.php"> 
    <div class="formCol"> 
     <label>Email:</label> 
     <input type="email" id="formEmail" name="email" autocomplete="off" placeholder="Your email address..." required/> 
    </div> 
    <div class="formCol midCol"> 
     <label id="floatMsg">Message (350 chars):</label> 
     <textarea id="formMessage" name="message" rows="5" cols="40" maxlength="350" placeholder="What have you got to say?" required></textarea> 

    </div> 
    <div class="formCol lastCol"> 
     <input type="submit" class="submit-btn" name="submit" value="Send" /> 
    </div> 
</form> 

...腳本

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script> 
<!--[if lt IE 9]><script src="js/modernizr.custom.js"></script><![endif]--> 
<script src="js/jquery.flexslider-min.js"></script> 
<script src="js/functions.js"></script> 
<script> 
    $(document).ready(function() { 
     $('#form').ajaxForm(function() { 
      alert("Thank you for your comment! I will receive it shortly and get back to you as soon as possible."); 
      document.getElementById("form").reset(); 
     }); 

    }); 
</script> 

發送電子郵件（PHP）

if (isset($_POST['submit'])) { 
    $email = htmlspecialchars($_POST['email']); 
    $comment = htmlspecialchars($_POST['message']); 



    /* Sending Email */ 
    $from_add = "Visitor"; 
    $to_add = "user@email.com"; 
    $subject = "The_Message_Subject"; 
    $message = " 
     Message Information 
     Email = $email 
     Message = $comment"; 

    $headers = "From: $from_add \r\n"; 
    $headers .= "Reply-To: $from_add \r\n"; 
    $headers .= "Return-Path: $from_add \r\n"; 
    $headers .= "X-Mailer: PHP \r\n"; 

    mail($to_add, $subject, $message, $headers); 
} 

Answer 1

形式復位後添加return false。另外表格ID是contactForm不只是form。

<script> 
    $(document).ready(function() { 
     $('#contactForm').ajaxForm(function() { 
      alert("Thank you for your comment! I will receive it shortly and get back to you as soon as possible."); 
      document.getElementById("form").reset(); 
      return false; 
     }); 
    }); 
</script>