2
通過執行該JPQL:如何通過JPA/Hibernate中的聚合列進行排序?
select o.key, count(o.id), sum(o.errors) from MyEntity o
group by o.key
休眠提交的SQL語句:
select
myentityn0_.key as col_0_0_,
count(myentityn0_.id) as col_1_0_,
sum(myentityn0_.errors) as col_2_0_
from
MYENTITY myentityn0_
group by
myentityn0_.key
但我怎麼可以用「按訂單」,在這種情況下不使用Hibernate的創建列名?如果我在JPQL中使用as
,則SQL不會更改。