使用SQL生成XML

Question

我試圖使用SQL生成的XML格式：

<ImportSession> 
    <Batches> 
    <Batch> 
     <BatchFields> 
     <BatchField Name="Field1" Value="1" /> 
     <BatchField Name="Field2" Value="2" /> 
     <BatchField Name="Field3" Value="3" /> 
     </BatchFields> 
    <Batch> 
    <Batches> 
</ImportSession> 

我使用SQL Server 2008中我寫此查詢：

SELECT 
    (SELECT 
     (SELECT 
       'Col' AS [@Name], 
       FiscalYear AS [@Value] 
      FROM [ICEM].[dbo].[ExportedBill] 
      WHERE ExportedBillID = 1 
      FOR XML PATH ('BatchField'), TYPE) 
    FROM [ICEM].[dbo].[ExportedBill] 
    WHERE ExportedBillID = 1 
    FOR XML PATH ('BatchFields'), ROOT ('Batch'), TYPE) 
FROM 
    [ICEM].[dbo].[ExportedBill] 
WHERE 
    ExportedBillID = 1 
FOR XML PATH ('Batches'), ROOT ('ImportSession') 

而且這個結果是：

<ImportSession> 
    <Batches> 
    <Batch> 
     <BatchFields> 
     <BatchField Name="Col" Value="2015" /> 
     </BatchFields> 
    </Batch> 
    </Batches> 
</ImportSession> 

我需要的是每個列都應該在BatchField中有一個條目。此外，我需要列名顯示在名稱中。所以，我應該得到：

<BatchField Name="FiscalYear" Value="2015" /> 
<BatchField Name="MeterNumber" Value="123456" /> 
<BatchField Name="Name" Value="John Smith" /> 
<BatchField Name="Utility" Value="Electricity" /> 

因此，誰能告訴我如何修改我的查詢來獲取我需要什麼？

編輯：

我想通了。我需要第二個嵌套的選擇。我需要每列一個。如果他們選擇繼續使用相同的標籤，以前的選擇，則信息是相同的父標籤

SELECT 
    (SELECT 
     (SELECT 
       'FiscalYear' AS [@Name], 
       FiscalYear AS [@Value] 
      FROM [ICEM].[dbo].[ExportedBill] 
      WHERE ExportedBillID = 1 
      FOR XML PATH ('BatchField'), TYPE), 
      (SELECT 'FiscalPeriod' AS [@Name], 
      FiscalPeriod AS [@Value] 
      FROM [PEEL_ICEM].[dbo].[ExportedBill] 
      WHERE ExportedBillID = 1 
      FOR XML PATH ('BatchField'), TYPE) 
    FROM [ICEM].[dbo].[ExportedBill] 
    WHERE ExportedBillID = 1 
    FOR XML PATH ('BatchFields'), ROOT ('Batch'), TYPE) 
FROM 
    [ICEM].[dbo].[ExportedBill] 
WHERE 
    ExportedBillID = 1 
FOR XML PATH ('Batches'), ROOT ('ImportSession') 

事情是，雖然下concatanated，會出現在該表中的70列。虐待現在，但如果有人知道更好的方式來做到這一點，請讓我知道。歡呼聲

Answer 1

您可以通過添加空白列分隔符來創建單獨的子元素。例如

DECLARE @T TABLE 
( FiscalYear INT, 
    MeterNumber INT, 
    Name VARCHAR(255), 
    Utility VARCHAR(255) 
); 
INSERT @T VALUES (2015, 123456, 'John Smith', 'Electricity'); 

SELECT [BatchField/@Name] = 'FiscalYear', 
     [BatchField/@Value] = FiscalYear, 
     '', 
     [BatchField/@Name] = 'MeterNumber', 
     [BatchField/@Value] = MeterNumber, 
     '', 
     [BatchField/@Name] = 'Name', 
     [BatchField/@Value] = Name, 
     '', 
     [BatchField/@Name] = 'Utility', 
     [BatchField/@Value] = Utility 
FROM @T 
FOR XML PATH('BatchFields'), ROOT('Batch'); 

其中給出：

<Batch> 
    <BatchFields> 
    <BatchField Name="FiscalYear" Value="2015" /> 
    <BatchField Name="MeterNumber" Value="123456" /> 
    <BatchField Name="Name" Value="John Smith" /> 
    <BatchField Name="Utility" Value="Electricity" /> 
    </BatchFields> 
</Batch>