Picasso自定義位圖變換方法

Question

我有一個函數，它將一個位圖作爲參數，並返回一個位圖。

public Bitmap setRoundedCornes(Bitmap b, int l, int r, int t, int b) 

使用畢加索之前，我用這個方法在應用程序中使用我的最後位之前。

現在我正在使用畢加索，我不確定如何應用此方法。

有沒有人有任何想法？

編輯

我現在有：

public static Bitmap getRoundedCornerBitmap(Bitmap bitmap, int topLeftX, int topLeftY, int topRightX, int topRightY, int bottomRightX, int bottomRightY, int bottomLeftX, int bottomLeftY) { 
    try { 
     final Paint paint = new Paint(); 
     final Rect rect = new Rect(0, 0, bitmap.getWidth(), bitmap.getHeight()); 
     Bitmap output = Bitmap.createBitmap(bitmap.getWidth(), bitmap.getHeight(), Bitmap.Config.ARGB_8888); 
     Canvas canvas = new Canvas(output); 
     // the float array passed to this function defines the x/y values of the corners 
     // it starts top-left and works clockwise 
     // so top-left-x, top-left-y, top-right-x etc 
     RoundRectShape rrs = new RoundRectShape(new float[]{topLeftX, topLeftY, topRightX, topRightY, bottomRightX, bottomRightY, bottomLeftX, bottomLeftY}, null, null); 
     canvas.drawARGB(0, 0, 0, 0); 
     paint.setAntiAlias(true); 
     paint.setColor(0xFF000000); 
     rrs.resize(bitmap.getWidth(), bitmap.getHeight()); 
     rrs.draw(canvas, paint); 
     paint.setXfermode(new PorterDuffXfermode(android.graphics.PorterDuff.Mode.SRC_IN)); 
     canvas.drawBitmap(bitmap, rect, rect, paint); 
     return output; 
    }catch(Exception e){ 

     return bitmap; 
    } 
} 

和

public class MyTransform implements Transformation { 
    @Override 
    public Bitmap transform(Bitmap source) { 
     //your logic to transform goes here 
     return getRoundedCornerBitmap(source, 20, 20, 20, 20, 0, 0, 0, 0); 
    } 

    @Override 
    public String key() { 
     return "circle"; 
    } 
} 

Answer 1

用於轉化創建一個類，它實現轉化

爲例如

public class MyTransform implements Transformation { 
    @Override 
    public Bitmap transform(Bitmap source) { 
     int size = Math.min(source.getWidth(), source.getHeight()); 

    int x = (source.getWidth() - size)/2; 
    int y = (source.getHeight() - size)/2; 

    Bitmap squaredBitmap = Bitmap.createBitmap(source, x, y, size, size); 
    if (squaredBitmap != source) { 
     source.recycle(); 
    } 

    Bitmap bitmap = Bitmap.createBitmap(size, size, source.getConfig()); 

    Canvas canvas = new Canvas(bitmap); 
    Paint paint = new Paint(); 
    BitmapShader shader = new BitmapShader(squaredBitmap, 
      BitmapShader.TileMode.CLAMP, BitmapShader.TileMode.CLAMP); 
    paint.setShader(shader); 
    paint.setAntiAlias(true); 

    float r = size/2f; 
    canvas.drawCircle(r, r, r, paint); 

    squaredBitmap.recycle(); 
    return bitmap; 
    } 

    @Override 
    public String key() { 
     return "circle"; 
    } 
} 

現在應用這種轉變可以畢加索使用這樣

Picasso.with(getContext()) 
    .load(url) 
    .transform(new MyTransform()) 
    .into(imageView, new com.squareup.picasso.Callback() { 
         @Override 
         public void onSuccess() { 
           // do something if its loaded successfully 
         } 

         @Override 
         public void onError() { 
          // do something if its not loaded successfully 
         } 
        }); 

Answer 2

是的，你可以申請轉換像這樣的：

public class CropSquareTransformation implements Transformation { 
    @Override public Bitmap transform(Bitmap source) { 
    int size = Math.min(source.getWidth(), source.getHeight()); 
    int x = (source.getWidth() - size)/2; 
    int y = (source.getHeight() - size)/2; 
    Bitmap result = Bitmap.createBitmap(source, x, y, size, size); 
    if (result != source) { 
     source.recycle(); 
    } 
    return result; 
    } 

    @Override public String key() { return "square()"; } 
} 

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