如何在SQL

Question

單查詢兩個結果結合起來，我有此查詢

Select 
    Count(IN_Invoices.in_id) NoOfInv, 
    sum(in_total) AMTsum, 
    CLOI_ClientOrderItems.cl_Id  
from 
(
    select 
     distinct MasterOrderId, 
     cl_Id 
    from CLOI_ClientOrderItems 
) as CLOI_ClientOrderItems 
inner Join IN_Invoices 
    on IN_Invoices.MasterOrderId=CLOI_ClientOrderItems.MasterOrderId 
group by CLOI_ClientOrderItems.cl_id 

查詢結果

 
noofinc amtsum  cl_id 
7   245  100000pri 
247  181110.29 100001pro 

Select 
    Count(IN_Invoices.in_id) NoOfInv, 
    AMTsum=sum(in_total) , 
    CLOI_ClientOrderItems.cl_Id  
from 
(
    select 
     distinct MasterOrderId, 
     cl_Id 
    from CLOI_ClientOrderItems 
) as CLOI_ClientOrderItems 
inner Join IN_Invoices 
    on IN_Invoices.MasterOrderId=CLOI_ClientOrderItems.MasterOrderId 
where datepart(mm,in_date_issued)=1 and datepart(yyyy,in_date_issued)=2014 
group by CLOI_ClientOrderItems.cl_id 

在此queryi

haveenterd月份這樣ITLL顯示，月記錄

 
noofinc amtsum cl_id   Grandtotal 
5  7.00  100000_Pri 7.00 
12  2510.12 100001_pro 2510.12 

但在此查詢中顯示如果我照耀處也每月應該顯示（見amtsum列的第一個查詢結果）錯誤的結果 Grandtotal是

 
245 
181110.29 

Answer 1

使用案例，以確定是否記錄是所需的月份。選擇所有記錄（no where子句）並使用該案例表達式來決定是否添加值或忽略它。在下面的例子中，我創建了一個flag_match標誌來增強可讀性。爲此，我必須先建立一個子查詢。這不是必需的;我更喜歡這種方式。

select 
    cl_id, 
    sum(case when month_match = 1 then 1 else 0 end) as count_invoices_in_month, 
    sum(case when month_match = 1 then in_total else 0 end) as sum_invoices_in_month, 
    count(*) as count_invoices_total, 
    sum(in_total) as sum_invoices_total 
from 
(
    select 
    i.in_id, 
    i.in_total, 
    cloi.cl_id, 
    case when datepart(mm, i.in_date_issued) = 1 
     and datepart(yyyy, i.in_date_issued) = 2014 then 
     1 
    else 
     0 
    end as month_match 
    from 
    (
    select distinct masterorderid, cl_id from cloi_clientorderitems 
) as cloi 
    inner join in_invoices i on i.masterorderid=cloi.masterorderid 
) 
group by cl_id;