如何創建測試執行的日誌文件

Question

我想創建一個測試控制器，並希望測試的執行被收集到一個文件。

我知道使用，三通和重定向測試腳本執行到某個文件，但我有興趣與蟒蛇在linux下做到這一點。

所以，每當執行測試時，應該得到創建的日誌文件，所有的執行日誌，包括標準輸入，輸出和錯誤應該得到收集到這個文件這種情況。

請求某些機構建議我，如何實現這種想法！

感謝 的OpenFile

Answer 1

打開並寫入文件：

mylogfile = 'bla.log' 
f = open(mylogfile, 'a') 
f.write('i am logging! logging logging!....loggin? timber!....') 
f.close() 

看在根目錄下有腳本 'bla.log' 和讀取，享受

Answer 2

您可以編寫一個函數像這樣：

def writeInLog(msg): 
    with open("log", "a") as f: 
     f.write(msg+"\n") 

它會打開文件「日誌「，然後附加（」a「）消息後跟一個換行符，然後關閉該文件。

Answer 3

# Save the current stream 
saveout = sys.stdout 


f = "a_log_file.log" 
fsock = open(f, 'w') 

# Set stream to file 
sys.stdout = fsock 

### 
# do something here 
# any print function will send the stream to file f 
### 

# Reset back the stream to what it was 
sys.stdout = saveout 
fsock.close() 

Answer 4

試試這個：

import sys 

# Save the current stream 
save_out = sys.stdout 

# Define the log file 
f = "a_log_file.log" 
# Append to existing log file. 
# Change 'a' to 'w' to recreate the log file each time. 
fsock = open(f, 'a') 

# Set stream to file 
sys.stdout = fsock 

### 
# do something here 
# any print function calls will send the stream to file f 
### 

# Reset back the stream to what it was 
# any print function calls will send the stream to the previous stream 
sys.stdout = save_out 
fsock.close() 

Answer 5

有幾個很好的日誌記錄模塊，從內置的logging，這裏是official cookbook。比較有趣的第三方庫是Logbook，這裏是一個相當裸例子只是皮毛其very cool features的表面：

import logbook 

def f(i,j): 
    return i+j 

logger = logbook.Logger('my application logger') 
log = logbook.FileHandler('so.log') 
log.push_application() 

try: 
    f(1, '2') 
    logger.info('called '+f.__name__) 
except: 
    logger.warn('failed on ') 


try: 
    f(1, 2) 
    logger.info('called '+f.__name__) 
except: 
    logger.warn('choked on, ') 

so.log則是這樣的：

[2011-05-19 07:40] WARNING: my application logger: failed on 
[2011-05-19 07:40] INFO: my application logger: called f