XML TO LINQ解析

Question

我有一個簡單的XML，使用XML TO LINQ分析，但是「代碼」，「預算」數據不能以表格方式，試過很多方法，一直無法有效解決，問老師是否可以幫助解決問題，謝謝你的幫助。

主程序：

using System.Collections.Generic; 
using System.ComponentModel; 
using System.Data; 
using System.Drawing; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 
using System.Windows.Forms; 
using System.Xml.Linq; 

namespace test_1015_empl 
{ 
    public partial class Form1 : Form 
{ 
    public Form1() 
    { 
     InitializeComponent(); 
    } 

    private void button1_Click(object sender, EventArgs e) 
    { 
     LinqExamples linq = new LinqExamples(); 
     linq.GetEmployeeList(); 
     dataGridView1.DataSource = linq.GetEmployeeList(); 
    } 

    private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e) 
    { 
    } 
} 

}

類

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 
using System.Xml.Linq; 

namespace test_1015_empl 
{ 
    internal class set 
    { 
    } 

public class Employee 
{ 
    public int EmployeeID { get; set; } 
    public string EmployeeName { get; set; } 
    public string EmployeePosition { get; set; } 
    public string EmployeeCountry { get; set; } 
    public Project[] Projects { get; set; } 
} 

public class Project 
{ 
    public string ProjectCode { get; set; } 
    public int ProjectBudget { get; set; } 
} 

public class LinqExamples 
{ 
    private List<Employee> employeeList; 

    public List<Employee> GetEmployeeList() 
    { 
     if (employeeList == null) 
      LoadXML(); 
     return employeeList; 
    } 

    private void LoadXML() 
    { 
     employeeList = 
      (
       from e in XDocument.Load(@"..\..\Employees.xml").Root.Elements("employee") 
       select new Employee 
       { 
        EmployeeID = (int)e.Element("id"), 
        EmployeeName = (string)e.Element("name"), 
        EmployeePosition = (string)e.Element("position"), 
        EmployeeCountry = (string)e.Element("country"), 
        Projects = 
        (
         from p in e.Elements("projects").Elements("project") 
         select new Project 
         { 
          ProjectCode = (string)p.Element("code"), 
          ProjectBudget = (int)p.Element("budget") 
         }).ToArray() 
       }).ToList(); 
    } 
} 

}

XML：

<?xml version="1.0"?> 
<employees> 
    <employee> 
    <id>1001</id> 
    <name>John</name> 
    <position>Developer</position> 
    <country>USA</country> 
    <projects> 
     <project> 
      <code>Orlando</code> 
      <budget>1000</budget> 
     </project> 
     <project> 
      <code>Rocket</code> 
      <budget>7000</budget> 
     </project> 
    </projects> 
</employee> 

<employee> 
    <id>1002</id> 
    <name>Tomas</name> 
    <position>QA</position> 
<country>USA</country> 
    <projects> 
     <project> 
      <code>Orlando</code> 
      <budget>1000</budget> 
     </project> 
     <project> 
      <code>Newman</code> 
      <budget>900</budget> 
     </project> 
    </projects> 
</employee> 

<employee> 
    <id>1003</id> 
    <name>Marina</name> 
    <position>QA</position> 
<country>Russia</country> 
    <projects> 
     <project> 
      <code>Orlando</code> 
      <budget>1000</budget> 
     </project> 
     <project> 
      <code>Newman</code> 
      <budget>900</budget> 
     </project> 
     <project> 
      <code>Rocket</code> 
      <budget>7000</budget> 
     </project> 
    </projects> 
</employee> 

<employee> 
    <id>1004</id> 
    <name>Suzan</name> 
    <position>Developer</position> 
<country>England</country> 
    <projects>   
     <project> 
      <code>Rocket</code> 
      <budget>7000</budget> 
     </project> 
    </projects> 
</employee> 

<employee> 
<id>1005</id> 
<name>Lucas</name> 
<position>IT</position> 
<country>England</country> 
<projects> 
    <project> 
    <code>Orlando</code> 
    <budget>1000</budget> 
    </project> 
    <project> 
     <code>Rocket</code> 
     <budget>7000</budget> 
    </project> 
    <project> 
     <code>Newman</code> 
    <budget>900</budget> 
    </project> 
    </projects> 
</employee> 
</employees> 

輸出結果，減少「代碼」，「預算」數據，如何使用分辨率？

Answer 1

您可以使用兩個DataGridView以及數據綁定作爲主/明細。

var employeesBindingSource = new BindingSource(); 
employeesBindingSource.DataSource = employeeList; 

var projectsBindingSource = new BindingSource(); 
projectsBindingSource.DataSource = employeesBindingSource; 
projectsBindingSource.DataMember = nameof(Employee.Projects); 

employeesDataGridView.DataSource = employeesBindingSource; 
projectsDataGridView.DataSource = projectsBindingSource; 

---

見全樣本：

你的員工

using System.Data; 
using System.Drawing; 
using System.Linq; 
using System.Windows.Forms; 
using System.Xml.Linq; 

namespace WindowsFormsApp1 
{ 
    public partial class Form1 : Form 
    { 
     public Form1() 
     { 
      //InitializeComponent(); 
      Size = new Size(600, 400); 

      var employeeList = 
      (
       from e in XDocument.Load("test.xml").Root.Elements("employee") 
       select new Employee 
       { 
        EmployeeID = (int)e.Element("id"), 
        EmployeeName = (string)e.Element("name"), 
        EmployeePosition = (string)e.Element("position"), 
        EmployeeCountry = (string)e.Element("country"), 
        Projects = 
        (
         from p in e.Elements("projects").Elements("project") 
         select new Project 
         { 
          ProjectCode = (string)p.Element("code"), 
          ProjectBudget = (int)p.Element("budget") 
         }).ToArray() 
       }).ToList(); 

      var employeesDataGridView = new DataGridView { Parent = this, Dock = DockStyle.Top }; 
      var projectsDataGridView = new DataGridView { Parent = this, Dock = DockStyle.Bottom }; 

      var employeesBindingSource = new BindingSource(); 
      employeesBindingSource.DataSource = employeeList; 

      var projectsBindingSource = new BindingSource(); 
      projectsBindingSource.DataSource = employeesBindingSource; 
      projectsBindingSource.DataMember = nameof(Employee.Projects); 

      employeesDataGridView.DataSource = employeesBindingSource; 
      projectsDataGridView.DataSource = projectsBindingSource; 
     } 
    } 

    public class Employee 
    { 
     public int EmployeeID { get; set; } 
     public string EmployeeName { get; set; } 
     public string EmployeePosition { get; set; } 
     public string EmployeeCountry { get; set; } 
     public Project[] Projects { get; set; } 
    } 

    public class Project 
    { 
     public string ProjectCode { get; set; } 
     public int ProjectBudget { get; set; } 
    } 
}