ORACLE SQL得到2個select語句

Question

檢索兩個值的差異，我們有2個非常簡單的SELECT語句：

SELECT value from table where date between DATE1 and DATE2 
SELECT value from table where date between DATE3 and DATE4 

我們需要一種方法來寫一個SQL語句，將獲得「價值」的區別這是從這兩個SQL語句返回的。

我們試過以下，但沒有成功：

SELECT value from table where date between DATE1 and DATE2 
minus 
SELECT value from table where date between DATE3 and DATE4 

任何建議高度讚賞。

Answer 1

未經測試，但應該工作：

SELECT 
    (SELECT value from table where date between DATE1 and DATE2) - 
    (SELECT value from table where date between DATE3 and DATE4) 
FROM dual; 

假設你SELECT value是保證返回一個值

Answer 2

SELECT value FROM TBL WHERE date BETWEEN DATE1 and DATE2 
AND value NOT IN (SELECT value FROM TBL WHERE date BETWEEN DATE3 AND DATE4) 

Answer 3

請試試這個：

SET SERVEROUTPUT ON 
DECLARE 
V_FIRST NUMBER := 0; 
V_SECOND NUMBER := 0; 
BEGIN 
    SELECT value into V_FIRST from table where rownum=1 and date between DATE1 and DATE2; 
    SELECT value into V_SECOND from table where rownum=1 and date between DATE3 and DATE4; 

    DBMS_OUTPUT.PUT_LINE (V_FIRST-V_SECOND); 
END; 

Answer 4

(
SELECT value from table where date between DATE1 and DATE2 
minus 
SELECT value from table where date between DATE3 and DATE4 
) 
union all 
(
SELECT value from table where date between DATE3 and DATE4 
minus 
SELECT value from table where date between DATE1 and DATE2 
) 

Answer 5

下面的語句笑對於你的情況ULD工作

(
SELECT value from table where date between DATE3 and DATE4 
minus 
SELECT value from table where date between DATE1 and DATE2 
) 
union 
(
SELECT value from table where date between DATE1 and DATE2 
minus 
SELECT value from table where date between DATE3 and DATE4 
) 

Answer 6

如果你覺得你內心的疑問可以給多個值，使用下面

SELECT 
(SELECT sum(value) from table where date between DATE1 and DATE2) - 
(SELECT sum(value) from table where date between DATE3 and DATE4) as answer 

FROM DUAL;