果園非內容一對多關係

Question

我是一種新鮮的果園。我想在這裏實現的是我的實體之間的關係。所以基本上ApiConfigurationRecord應該有一個ApiParameterRecord列表。但是當我執行這個動作時，沒有任何東西正在被保存。此外，如果它保存，希望它會自動延遲加載它的孩子。順便說一句，我試圖以非內容的方式（沒有ContentPart或ContentPartRecord）。

好吧這是我的代碼：

public class ApiConfigurationRecord 
{ 
    public ApiConfigurationRecord() 
    { 
     if (Parameters == null) 
      Parameters = new List<ApiParameterRecord>(); 
    } 

    public virtual int Id { get; set; } 

    public virtual string Name { get; set; } 

    public virtual string Description { get; set; } 

    public virtual IList<ApiParameterRecord> Parameters { get; set; } 
} 

public class ApiParameterRecord 
{ 
    public virtual int Id { get; set; } 

    public virtual string Name { get; set; } 
} 

public class Migrations : DataMigrationImpl 
{ 
    public int Create() 
    { 
     SchemaBuilder.CreateTable("ApiConfigurationRecord", table => table 
      .Column<int>("Id", column => column.PrimaryKey().Identity()) 
      .Column<string>("Name", column=> column.NotNull()) 
      .Column<string>("Description", column => column.WithLength(500)) 
      ); 

     SchemaBuilder.CreateTable("ApiParameterRecord", table => table 
      .Column<int>("Id", column => column.PrimaryKey().Identity()) 
      .Column<int>("ApiConfigurationRecord_Id") 
      .Column<string>("Name", column => column.NotNull()) 
      ); 

     return 1; 
    } 
} 

我的控制器動作：

public ActionResult TestInsert() 
    { 

     var record = new ApiConfigurationRecord() { Name = "Test 1", Description = "Some descripton" }; 
     record.Parameters.Add(new ApiParameterRecord() { Name = "Param1" }); 
     this.ApiConfigurationRepository.Create(record); 

     return Content("Inserted"); 
    } 

Answer 1

實際上你需要連接兩個項目。

public class ApiParameterRecord 
{ 
    public virtual int Id { get; set; } 

    public virtual string Name { get; set; } 

    public virtual ApiConfigurationRecord ApiConfigurationRecord { get; set; } 
} 

至於創建，我不會認爲它會自動創建子項，但我不知道。試試這個：

var record = new ApiConfigurationRecord() { Name = "Test 1", Description = "Some descripton" }; 
this.ApiConfigurationRepository.Create(record); 
var child1 = new ApiParameterRecord() { Name = "Param1", ApiConfigurationRecord = record }; 
ApiParameterRepository.Create(child1);