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我有一個字符串Python:如何從沒有索引的字符串中獲取子串?
s = "* * * * * * * = a b = c b = * * * * * * * "
,我想打印的每個項目=「*」包含前7項和後7,如子:
* * * * * * * = a b = c b = *
* * * * * * = a b = c b = * *
* * * * * = a b = c b = * * *
* * * * = a b = c b = * * * *
* * * = a b = c b = * * * * *
* * = a b = c b = * * * * * *
* = a b = c b = * * * * * * *
如果使用的嘗試指數是這樣的:
items = s.split(' ')
for i in items:
s = items.index(i)
start = s - 7
stop = s + 8
print items[start:stop]
的問題是,如果一個元素在列表中出現第二次,腳本列表中第一次出現的索引,你會得到這樣的:
* * * * * * * = a b = c b = *
* * * * * * = a b = c b = * *
* * * * * = a b = c b = * * *
* * * * * * * = a b = c b = * etc.
任何人都可以請幫助我嗎?
這功課嗎? – 2011-03-09 19:36:32