如何設置查詢以獲得如下結果？

如何讓這兩行的結果，兩列我的疑問是 -如何設置查詢以獲得如下結果？

select tt.* from wp_terms AS tt where tt.terms_id='" . $establishment['term_id'] . "' AND tt.meta_key ='phone'; 
select tt.* from wp_terms AS tt where tt.terms_id='" . $establishment['term_id'] . "' AND tt.meta_key ='location';

每個查詢給我造成的

meta_id terms_id meta_key meta_value 
6926  16   phone  0000 

meta_id terms_id meta_key meta_value 
6927 16   location xxx

現在我想作爲導致

meta_id terms_id meta_value  meta_value1 
6926  16  0000   xxx

請幫忙謝謝

來源

2011-12-02 Sparkx

你問我們如何獲取2行與一個查詢？ –

SELECT t.meta_id, t.terms_id, t.meta_value, tt.metaValue AS meta_value1 
FROM wp_terms AS t 
INNER JOIN wp_terms AS tt ON t.terms_id = tt.terms_id 
    AND t.meta_key = 'phone' 
    AND tt.meta_key = 'location' 
WHERE t.terms_id='" . $establishment['term_id'] . "'

來源

2011-12-02 08:08:05

，其優秀的感謝之手 – Sparkx

也許就是這樣。

select phone.meta_id, phone.terms_id, phone.meta_value as phone, location.meta_value as location 
from 
(select tt.* from wp_terms AS tt where tt.terms_id='" . $establishment['term_id'] . "' AND tt.meta_key ='phone') phone, 
(select tt.* from wp_terms AS tt where tt.terms_id='" . $establishment['term_id'] . "' AND tt.meta_key ='location') location 
where phone.meta_id = location.meta_id

來源

2011-12-02 08:09:49

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