如何獲得連續時間戳之間差異的BigQuery

Question

我有一個表，看起來像這樣：

ID DateTime 
1  5-1-16 12:25:13 
1  5-1-16 12:28:46 
2  5-1-16 12:25:18 
2  5-1-16 12:29:34 

我要找到每個ID每個連續的時間戳之間在幾秒鐘的差異。有沒有辦法在BigQuery中做到這一點？我有幾千條記錄。我知道我需要先隔離時間。

Answer 1

試試下面

SELECT 
    ID, 
    TIMESTAMP_TO_SEC(TIMESTAMP(DateTime))-TIMESTAMP_TO_SEC(TIMESTAMP(prev_DateTime)) AS diff, 
FROM (
    SELECT 
    ID, 
    DateTime, 
    LAG(DateTime) OVER(PARTITION BY ID ORDER BY DateTime) AS prev_DateTime 
    FROM 
    (SELECT 1 AS ID, '2016-05-01 12:25:13' AS DateTime), 
    (SELECT 1 AS ID, '2016-05-01 12:28:46' AS DateTime), 
    (SELECT 2 AS ID, '2016-05-01 12:25:18' AS DateTime), 
    (SELECT 2 AS ID, '2016-05-01 12:29:34' AS DateTime) 
) 

添加

SELECT 
    ID, 
    TIMESTAMP_TO_SEC(TIMESTAMP(DateTime))-TIMESTAMP_TO_SEC(TIMESTAMP(prev_DateTime)) AS diff, 
FROM (
    SELECT 
    ID, 
    DateTime, 
    LAG(DateTime) OVER(PARTITION BY ID ORDER BY DateTime) AS prev_DateTime 
    FROM YourTable 
) 

我注意到 - 看起來像你的日期時間字段有着不同尋常的形式 - '16年5月1日12時29分34秒'
如果這是您執行上述查詢時遇到的問題 - 您可以嘗試下面的一個
請注意：對於此查詢，您n eed to enable Standard SQL

SELECT 
    ID, 
    UNIX_SECONDS(DateTime) - UNIX_SECONDS(prev_DateTime) AS diff 
FROM (
    SELECT 
    ID, 
    DateTime, 
    LAG(DateTime) OVER(PARTITION BY ID ORDER BY DateTime) AS prev_DateTime 
    FROM (
    SELECT 
     ID, 
     PARSE_TIMESTAMP("%m-%d-%y %H:%M:%S", DateTime) AS DateTime 
    FROM YourTable 
) 
)