我使用以下代碼在服務器上傳圖像,並且它可以正常工作。但我會傳遞一些參數,我試圖通過「價值」作爲「測試」,但不起作用。Android |上傳帶有參數的圖像
public int uploadFile(File selectedFile){
int serverResponseCode = 0;
HttpURLConnection connection;
DataOutputStream dataOutputStream;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
String selectedFilePath = selectedFile.getAbsolutePath();
int bytesRead,bytesAvailable,bufferSize;
byte[] buffer;
int maxBufferSize = 1024 * 1024;
if (!selectedFile.isFile()){
//dialog.dismiss();
return 0;
}else {
try{
FileInputStream fileInputStream = new FileInputStream(selectedFile);
URL url = new URL(ServerTools.SERVER+"profile/test.php");
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);//Allow Inputs
connection.setDoOutput(true);//Allow Outputs
connection.setUseCaches(false);//Don't use a cached Copy
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("ENCTYPE", "multipart/form-data");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
connection.setRequestProperty("uploaded_file",selectedFilePath);
//creating new dataoutputstream
dataOutputStream = new DataOutputStream(connection.getOutputStream());
//writing bytes to data outputstream
dataOutputStream.writeBytes(twoHyphens + boundary + lineEnd);
dataOutputStream.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
+ selectedFilePath + "\"" + lineEnd);
dataOutputStream.writeBytes(lineEnd);
//returns no. of bytes present in fileInputStream
bytesAvailable = fileInputStream.available();
//selecting the buffer size as minimum of available bytes or 1 MB
bufferSize = Math.min(bytesAvailable,maxBufferSize);
//setting the buffer as byte array of size of bufferSize
buffer = new byte[bufferSize];
//reads bytes from FileInputStream(from 0th index of buffer to buffersize)
bytesRead = fileInputStream.read(buffer,0,bufferSize);
//loop repeats till bytesRead = -1, i.e., no bytes are left to read
while (bytesRead > 0){
//write the bytes read from inputstream
dataOutputStream.write(buffer,0,bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable,maxBufferSize);
bytesRead = fileInputStream.read(buffer,0,bufferSize);
}
//PARAMS!!!
dataOutputStream.writeBytes(twoHyphens + boundary + lineEnd);
dataOutputStream.writeBytes("Content-Disposition: form-data; name=\"value\"" + lineEnd);
dataOutputStream.writeBytes(lineEnd);
dataOutputStream.writeBytes("test" + lineEnd);
dataOutputStream.writeBytes(twoHyphens + boundary + lineEnd);
dataOutputStream.writeBytes(lineEnd);
dataOutputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
serverResponseCode = connection.getResponseCode();
String serverResponseMessage = connection.getResponseMessage();
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line;
StringBuilder responseOutput = new StringBuilder();
while ((line = br.readLine()) != null) {
responseOutput.append(line);
}
br.close();
Log.i("Test", "Server Response is: " + serverResponseMessage + ": " + serverResponseCode+ " -> "+responseOutput);
//closing the input and output streams
fileInputStream.close();
dataOutputStream.flush();
dataOutputStream.close();
}catch (Exception e){
e.printStackTrace();
}
}
return serverResponseCode;
}
我的PHP服務器很簡單:
<?php
$wp = $_FILES['uploaded_file']['tmp_name'];
move_uploaded_file($wp,"test.jpg");
echo "value: ".$_POST["value"];
?>
但Log.d打印:Server Response is: OK: 200 -> value:
我怎麼能傳遞一些參數應用正確地將?
謝謝!解決方案易於實現,它的工作完美。 –