我有以下表格:mysql - 如何獲取每月發佈或評論的獨特活躍用戶數量?
內容:CONTENT_ID,USER_ID,POST_DATE
評論:COMMENT_ID,USER_ID,COMMENT_DATE
我怎樣才能通過分組活動的唯一用戶的計數月和年? 活躍將意味着用戶在該月份發佈或評論。
我有以下表格:mysql - 如何獲取每月發佈或評論的獨特活躍用戶數量?
內容:CONTENT_ID,USER_ID,POST_DATE
評論:COMMENT_ID,USER_ID,COMMENT_DATE
我怎樣才能通過分組活動的唯一用戶的計數月和年? 活躍將意味着用戶在該月份發佈或評論。
SELECT
T.action_year,
T.action_month,
COUNT(T.user_id) active_users
FROM
(
SELECT DISTINCT user_id, YEAR(post_date) action_year, MONTH(post_date) action_month FROM content
UNION
SELECT DISTINCT user_id, YEAR(comment_date) action_year, MONTH(comment_date) action_date FROM comment
) T
GROUP BY
T.action_year,
T.action_month
ORDER BY
T.action_year ASC,
T.action_month ASC
哇,很棒的工作!謝謝 – MotoTribe 2012-04-22 02:02:28
這未經測試。
select count(table1.user_id), table1.user_id
from table1 table2
where table1.user_id = table2.user_id
And table2.comment_date like 'may'
試試這個
select TO_CHAR(order_dt,'MON-YYYY'), count(distinct User_ID) cnt from [orders]
where User_ID in
(select User_ID from
(select a.User_ID from [orders] a,
(select a.User_ID,count (a.order_dt) from [orders] a
where a.order_dt > (select max(b.order_dt)-365 from [orders] b where a.User_ID=b.User_ID)
group by a.User_ID
having count(order_dt)>1) b
where a.User_ID=b.User_ID) a
)
group by TO_CHAR(order_dt,'MON-YYYY');
1)如果在同一個月內用戶的信息和評論,它應該被計算兩次? 2)如果用戶在不同的月份發佈和評論,是否應該每月計算一次? – 2012-04-22 02:05:38