無法比較兩個浮點數

Question

我想匹配兩個浮點數但低於無法檢查：

https://jsfiddle.net/mcsab3aa/2/

JS代碼：

$('#checkButton').click(function() { 
    var getusertarget = parseFloat(jQuery("#targetval").val()); 
    var currentval = $("#demo").find("h1").html(); 
    currentval = parseFloat(currentval.replace('$','')); 
    console.log(currentval); 
    console.log(getusertarget); 
    var dividerval = (currentval/targetval); // it should be 1 
    console.log(dividerval); 
    if (dividerval==1) { 
     $('.coins_drags').hide(); 
     //$("#demo").find("h1").html('$' + sum.toFixed(2) + '<br />Great job'); 
     console.log('great'); 
} 
    else { 
     //$("#demo").find("h1").html('$' + sum.toFixed(2) + '<br />Try again'); 
     //sum = 0; 
     console.log('try'); 
    } 

}); 

Answer 1

var dividerval = (currentval/targetval); 

targetval是不確定的。你可能想要做的：

var dividerval = (currentval/getusertarget); 

Answer 2

嘗試這樣

var dividerval = (currentval/getusertarget); 

，而不是

var dividerval = (currentval/targetval); 

Answer 3

https://jsfiddle.net/mcsab3aa/4/

var h1 = $("#demo").find("h1"), 
    targetVal = f2num(h1.text()), 
    current = $("#targetval"), 
    msg = $('.msg'); 

msg.text('click after typing your guess'); 

$('#checkButton').click(function() { 
    if (current.val() == targetVal) { 
     msg.text('Great job'); 
     h1.html('$' + targetVal).show(); 
    } else { 
     h1.hide(); 
     msg.text('try again!'); 
    } 

}); 

function f2num(n) { 
    return parseFloat((n+"").replace(/[^0-9\.]+/g, '')); 
} 

的問題是，你試圖解析數與$中。並且處理程序顛倒了。