Bukkit /插口API：映射銷燬器和受害者

Question

我想給銷燬器名稱添加爲重點，和值，進入我的HashMap這就是所謂的damageCheck的受害者的名字。這全部在EntityDamageByEntityEvent完成。但是，當我嘗試存儲受害者和損害者時，一切都出錯了。

代碼：

private HashMap<String, String> damageCheck = new HashMap<String, String>(); 

@EventHandler 
public void onEntityDamageByEntityEvent(EntityDamageByEntityEvent event) { 

    if(event.getEntity() instanceof Player || event.getDamager() instanceof Player) { 
     Player victim = (Player) event.getEntity(); 
     Player damager = (Player) event.getDamager(); 

     String victimName = victim.getDisplayName(); // getting the victim name 
     String damagerName = damager.getDisplayName(); // getting the damager name 

     Bukkit.getServer().broadcastMessage(""); 
     Bukkit.getServer().broadcastMessage(victim.getDisplayName() + " is the victim!"); 
     Bukkit.getServer().broadcastMessage(damager.getDisplayName() + " is the damager!"); 
     Bukkit.getServer().broadcastMessage(""); 

     try { 
      if(!damageCheck.containsKey(damagerName)) { 
       damageCheck.put(victimName, damagerName); 

       Bukkit.getServer().broadcastMessage(""); 
       Bukkit.getServer().broadcastMessage(damageCheck.get(victimName) + " is victim!"); 
       Bukkit.getServer().broadcastMessage(damageCheck.get(damagerName) + " is damager!"); 
       Bukkit.getServer().broadcastMessage(""); 
      } else if(damageCheck.containsKey(damagerName)) { 
       damageCheck.replace(damagerName, damagerName, damagerName); 

       Bukkit.getServer().broadcastMessage(""); 
       Bukkit.getServer().broadcastMessage(damageCheck.get(victimName) + " is victim!"); 
       Bukkit.getServer().broadcastMessage(damageCheck.get(damagerName) + " is damager!"); 
       Bukkit.getServer().broadcastMessage(""); 
      } 
     } catch (NullPointerException e) { 
      // do nothing lol 
     } 

    } else { 
     Bukkit.getServer().broadcastMessage("There is no entity or damager!"); 
    } 
} 

的第一條消息是正確的。 GetSparked是受害者和Fendyk是損害者。但在第二條消息中，當試圖從hashmap中獲取名稱時，輸出的值是錯誤的。

編輯：我換了 damageCheck.put（victimName，damagerName）; 至 damageCheck.put（damagerName，victimName）;

但它現在給受害者null（第一次擊中），爲什麼？

Answer 1

所以，我測試了這樣的一個完整的新方式，因爲我真的不知道你指的，反正這是代碼，我覺得什麼是你真正需要的

無需爲new HashMap <String, String>

private HashMap<String, String> damageCheck = new HashMap<>(); 

代碼：

@EventHandler 
public void onEntityDamageByEntityEvent(EntityDamageByEntityEvent event) { 

    if(!(event.getDamager() instanceof Player) || !(event.getEntity() instanceof Player)) return; 

    String damagerName = event.getDamager().getName(); 
    String victimName = event.getEntity().getName(); 

    damageCheck.put(victimName, damagerName); 

    Bukkit.broadcastMessage(ChatColor.GRAY + "" + ChatColor.STRIKETHROUGH + "-------------[ X ]-------------"); 
    Bukkit.broadcastMessage(ChatColor.DARK_AQUA + damagerName + ChatColor.GRAY + " is the damager"); 
    Bukkit.broadcastMessage(ChatColor.DARK_AQUA + victimName + ChatColor.GRAY + " is the victim"); 
    Bukkit.broadcastMessage(ChatColor.GRAY + "" + ChatColor.STRIKETHROUGH + "-------------[ X ]-------------"); 

    Bukkit.getLogger().info(damageCheck.toString()); 

} 

從散刪除實體數據雖然這是不準確的，有時

@EventHandler 
public void onEntityDeathEvent(EntityDeathEvent event){ 
    damageCheck.remove(event.getEntity().getName()); 
    damageCheck.remove(event.getEntity().getKiller().getName()); 
} 

您可以刪除只隊員檢查，它會在任何實體工作 只是刪除

if(!(event.getDamager() instanceof Player) || !(event.getEntity() instanceof Player)) return;