如何加入使用透視兩條表與1個表結合兩個領域

Question

我有兩個表格式

Job_Skill

 ID_Skill Min_Job Idea_Job Max_Job 
    ===================================== 
     1  0   0  1 
     2  0   1  1 
     7  1   1  1 
     8  1   1  1 

Job_Education

 Degree_Job Field_Job Min_Job Idea_Job Max_Job 
     =================================================== 
       7  37   0   0   1 
       7  106  0   1   1 
       13  37   1   1   1 
       13  106  1   1   1 

我要顯示這樣的

Criteria 1 2 7 8 [ 7 37 ] [ 7 106 ] [13 37] [13 106] 
    ============================================================= 
    Min  0 0 1 1 1   1   0   0 
    Ideal  0 1 1 1 0   1   1   1 
    Max  1 1 1 1 1   1   1   1 

我如何在樞軸中實現這一點。如果您有其他方法，請提出建議。

Answer 1

這就是答案。我有我想要的結果。該查詢是動態的。

Declare @Skill NVARCHAR(MAX), 
     @Degree_Field NVARCHAR(MAX), 
     @Experience NVARCHAR(MAX), 
     @query NVARCHAR(MAX) 


    select @Skill = 
       STUFF((
         select SEQ 
         From 
         (
          SELECT SEQ = (',' + QUOTENAME(Skill_Name)) 
          From 
          (
          select Skill_Meta.Skill_Name,Min_Job, Ideal_Job, Max_Job 
          FROM Job_Skill 
          Inner Join Skill_Meta On Skill_Meta.ID_SKL = Job_Skill.ID_SKL_Job 
          )SKL 

          UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U 
         ) SKL 

         GROUP By SEQ 
         FOR XML PATH(''), TYPE 
         ).value('.', 'NVARCHAR(MAX)') 
         ,1,1,'') 

    select @Degree_Field = 
       STUFF((
         select SEQ 
         From 
         (
          SELECT SEQ = (',' + QUOTENAME(cast(CONCAT(Degree_Job,' ', Field_Job) as varchar(10)))) 
          FROM Job_Education 
          UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U 
         ) SKL 

         GROUP By SEQ 
         FOR XML PATH(''), TYPE 
         ).value('.', 'NVARCHAR(MAX)') 
         ,1,1,'') 
    select @Experience = 
       STUFF((
         select SEQ 
         From 
         (
          SELECT SEQ = (',' + QUOTENAME(cast(Experience_Job as varchar(10)))) 
          FROM Job_Experience 
          UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U 
         ) SKL 

         GROUP By SEQ 
         FOR XML PATH(''), TYPE 
         ).value('.', 'NVARCHAR(MAX)') 
         ,1,1,'') 

    set @query = 
      ';With 
      P1_Src As 
      (
       SELECT ID_Job,Skill_Name, Val, Col 
       FROM Job_Skill 
       Inner Join Skill_Meta On Skill_Meta.ID_SKL = Job_Skill.ID_SKL_JOB 
       UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U 

      ), 
      P1 AS 
      (
       SELECT ID_Job,Col,'+@Skill+' 
       FROM P1_Src 
       PIVOT (MAX(Val) FOR Skill_Name IN ('+@Skill+')) AS Pa 
      ), 

      P2_Src As 
      (
       SELECT ID_Job,CONCAT(Degree_Job,'' '', Field_Job) as DegreeField, Val, Col 
       FROM Job_Education 
       UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U 
      ), 

      P2 AS 
      (
       SELECT ID_Job,Col,'+@Degree_Field+' 
       FROM P2_Src 
       PIVOT (MAX(Val) FOR DegreeField IN ('+@Degree_Field+')) AS Pb 
      ), 

      P3_Src As 
      (
       SELECT ID_Job,Experience_Job, Val, Col 
       FROM Job_Experience 
       UNPIVOT (Val FOR Col IN (Min_Job, Ideal_Job, Max_Job)) AS U 
      ), 

      P3 AS 
      (
       SELECT ID_Job,Col,'+@Experience+' 
       FROM P3_Src 
       PIVOT (MAX(Val) FOR Experience_Job IN ('+@Experience+')) AS Pc 
      ) 



      select P1.ID_Job,P1.Col,P1.'+@Skill+',P2.'+@Degree_Field+',P3.'+@Experience+' 
      From P1 
      Inner Join P2 On P1.ID_Job = P2.ID_Job and P1.Col = P2.Col 
      Inner Join P3 On P1.ID_Job = P3.ID_Job and P1.Col = P3.Col' 

exec sp_executesql @query 

Answer 2

declare @job_skill table (id_skill int,min_job int ,ideal_job int ,max_job int) 
insert into @job_skill 
VAlues 
(  1 ,  0 ,   0 ,  1), 
(  2 ,  0 ,   1 ,  1), 
(  7 ,  1 ,   1 ,  1), 
(  8 ,  1 ,   1 ,  1) 


declare @Job_Education table (Degree_Job int, Field_Job int, Min_Job int, Ideal_Job int, Max_Job int) 
insert into @job_education 
values 
(    7 ,  37 ,  0 ,  0 ,  1), 
(    7 ,  106 ,  0 ,  1 ,  1), 
(    13 ,  37 ,  1 ,  1 ,  1), 
(    13 ,  106 ,  1 ,  1 ,  1) 

/* 
I want to display like this 

    Criteria 1 2 7 8 [ 7 37 ] [ 7 106 ] [13 37] [13 106] 
    ============================================================= 
    Min  0 0 1 1 1   1   0   0 
    Ideal  0 1 1 1 0   1   1   1 
    Max  1 1 1 1 1   1   1   1 
*/ 

select * 
from 
(
select 1 as seq,'Min' as Criteria,cast(id_skill as char(10)) as COL, min_job jobval 
from @job_skill 
union 
select 2,'Ideal',cast(id_skill as char(10)) as criteria,ideal_job 
from @job_skill 
union 
select 3,'Max',cast(id_skill as char(10)) as criteria, Max_job 
from @job_skill 
union 
select 1, 'Min','(' + rtrim(cast(degree_job as char(4))) + ' ' + rtrim(cast(field_job as char(4))) +')' , min_job 
from @job_education 
union 
select 2, 'Ideal','(' + rtrim(cast(degree_job as char(4))) + ' ' + rtrim(cast(field_job as char(4))) +')' , ideal_job 
from @job_education 
union 
select 3, 'Max','(' + rtrim(cast(degree_job as char(4))) + ' ' + rtrim(cast(field_job as char(4))) +')' , Max_job 
from @job_education 
) s 
pivot (max(jobval) for col in([1],[2],[7],[8],[(7 37)],[(7 106)],[(13 37)],[(13 106)])) pvt 
order by seq