我試圖用一些還記得我班,現在的問題是,我得到調用一個成員函數準備()一個非對象在PDO
Call to a member function prepare() on a non-object
和我沒有得到任何錯誤的:
的index.php:
try {
$connection = new PDO('mysql:host=localhost;dbname=ibids', 'root', '');
}
catch (PDOException $e)
{
printf ($e);
}
$storage = new Rememberme_Storage_PDO($connection);
$rememberMe = new Rememberme($storage);
我發送連接到這個文件: pdo.php 和使用有此代碼:
class Rememberme_Storage_PDO extends Rememberme_Storage_DB {
/**
*
* @var PDO
*/
protected $connection;
public function getConnection() {
return $this->connection;
}
public function setConnection(PDO $connection) {
try {
$this->connection = $connection;
}
catch (PDOException $e)
{
printf ($e);
}
}
}
而且我在這裏有錯誤此功能:
** Rememberme_Storage_PDO類
public function storeTriplet($credential, $token, $persistentToken, $expire=0) {
$sql = "INSERT INTO {$this->tableName}({$this->credentialColumn}, " .
"{$this->tokenColumn}, {$this->persistentTokenColumn}, " .
"{$this->expiresColumn}) VALUES(?, SHA1(?), SHA1(?), ?)";
$query = $this->connection->prepare($sql);
if(!$query->execute(array($credential, $token, $persistentToken, date("Y-m-d H:i:s", $expire))))
{
die('excute faild');
}
}
在這個函數說:
Fatal error: Call to a member function prepare() on a non-object in F:\wamp\www\rememberme-master\src\Rememberme\Storage\PDO.php on line 44
我是ne在PDO的wbie,我做錯了什麼?
當你的var_dump($這個 - >連接),您能得到什麼? –
沒有我保持相同的錯誤,並沒有任何其他錯誤,我tryed死了,var_dump,趕上,一切都顯示相同的錯誤..順便說一句,這種好辦法與getConenction方法連接? –