Question

我有下面的連接代碼：

$this->connection->prepare("CALL CreateRecord('testingRecord')") 

它給了我下面的錯誤：

$this->connectionString = 'mysql:host=' . db_config_DBConfig::$MySQLserverName . ';dbname=' . db_config_DBConfig::$MySQLdbName . ';port=' . db_config_DBConfig::$MySQLport .';connect_timeout=15'; 
    $this->connection = new PDO($this->connectionString, db_config_DBConfig::$MySQLuserName, db_config_DBConfig::$MySQLpassCode); 
    $this->connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

這樣做後：

Fatal error: Call to a member function prepare() on a non-object in 

當我打印使用的var_dump的對象時，它給了我這樣的：

object(db_mysql_DBConnect)#1 (3) { ["connectionString":"db_mysql_DBConnect":private]=> string(70) "mysql:host=localhost;dbname=testingrecord;port=3306;connect_timeout=15" ["connection"]=> object(PDO)#2 (0) { } ["assocData":"db_mysql_DBConnect":private]=> array(0) { } } 

我不知道我在這裏錯過了什麼。任何幫助將不勝感激...

Answer 1

我猜PDO構造函數因連接憑證錯誤而失敗。如果連接失敗，將ERRMODE_EXCEPTION直接傳遞給構造函數以使連接觸發異常：

$this->connection = new PDO(
    $this->connectionString, 
    db_config_DBConfig::$MySQLuserName, 
    db_config_DBConfig::$MySQLpassCode, 
    array (
     PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION 
    ) 
);