獲取查詢結果的金額範圍內同一查詢

Question

我有一個查詢：

SELECT case 

when Submission__bTracking = 'Phone' then 'Phone' 
when Submission__bTracking = 'Web' then 'Web' 
when Submission__bTracking = 'Email' then 'Email 
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support 
when Submission__bTracking = 'Verbal' then 'Verbal Request' 
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax/Form' 

End as Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

GROUP BY Submission__bTracking 

產生以下結果：

Sub_Tracking    tickets 
Email      36 
Fax/Form     1 
@ Live Tech Support   18 
Phone      441 
Web       41 

我怎麼還生產中所有的門票總和同樣的查詢？

象下面這樣：

Sub_Tracking    tickets 
Email      36 
Fax/Form     1 
@ Live Tech Support   18 
Phone      441 
Web       41 
ALL       537 

感謝您的幫助！

Answer 1

您可以使用UNION，只是在結果集中增加一個行：

YOUR QUERY 

UNION ALL 
select 'ALL' as Sub_Tracking, 
COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

Answer 2

你可以做

...previous lines omitted 
GROUP BY Submission__bTracking 
UNION 
SELECT 'ALL' as Sub_Tracking, count(Submission__bTracking) as tickets 
FROM dbo.MASTER30 
WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

Answer 3

這裏有真正的兩種選擇。一是工會您有另外一個，計算所有的門票，像

SELECT case 

when Submission__bTracking = 'Phone' then 'Phone' 
when Submission__bTracking = 'Web' then 'Web' 
when Submission__bTracking = 'Email' then 'Email 
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support 
when Submission__bTracking = 'Verbal' then 'Verbal Request' 
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax/Form' 

End as Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

GROUP BY Submission__bTracking 

UNION ALL 

SELECT "All" AS Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

初始查詢另一種選擇是WITH ROLLUP使用（如http://dev.mysql.com/doc/refman/5.6/en/group-by-modifiers.html）

這將是這樣的：

SELECT case 

when Submission__bTracking = 'Phone' then 'Phone' 
when Submission__bTracking = 'Web' then 'Web' 
when Submission__bTracking = 'Email' then 'Email 
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support 
when Submission__bTracking = 'Verbal' then 'Verbal Request' 
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax/Form' 

End as Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

GROUP BY Submission__bTracking WITH ROLLUP 

後來的選項將不輸出「ALL」行，但它是短了很多......此外，您不能使用ORDER BY和WITH ROLLUP在一起，所以知道，提前爲好。

在這兩者之間，我可能會使用第一個選項....這是同由誰回答，但我會使用UNION ALL而不是UNION的其他人提供的兩個。這是一個挑剔的細節，但如果你不需要它們，爲什麼還要重複檢查。欲瞭解更多關於UNION VS UNION ALL，請上網：What is the difference between UNION and UNION ALL?）