獲取字典

Question

NSMutableArray *tmpMutArr = [NSMutableArray arrayWithArray:allObjectsArray]; 
    NSLog(@"The content of array is%@",tmpMutArr); 

    int index; 

    for (int i=0;i<[tmpMutArr count];i++) 
    { 
    if([[tmpMutArr objectAtIndex:i] isKindOfClass:[NSDictionary class]]) 
    { 
    NSMutableDictionary *tempDict = [tmpMutArr objectAtIndex:i]; 
     if([[tempDict valueForKey:@"Name"] isEqualToString:[NSString stringWithFormat:@"%@", nameString]]) 
    { 
    index = i; 

    } 
    } 
    } 

    [tmpMutArr replaceObjectAtIndex:index withObject:[NSDictionary dictionaryWithDictionary:mutDict]]; 

此代碼不能替換tmpMutArr的匹配對象的正確的索引，因爲我希望它，但在tmpMutArr，而不是取代所有對象。如何只替換我想要的索引？

我知道，包含替換之前的所有對象tmpMutArr，所以我只需要指定正確，我認爲指數。如何做？

Answer 1

NSMutableArray *tmpMutArr = [NSMutableArray arrayWithArray:allObjectsArray]; 
NSLog(@"The content of array is%@",tmpMutArr); 

int index; 

for (int i=0;i<[tmpMutArr count];i++) 
{ 
    if([[tmpMutArr objectAtIndex:i] isKindOfClass:[NSDictionary class]]) 
    { 
     NSMutableDictionary *tempDict = [tmpMutArr objectAtIndex:i]; 
     if([[tempDict valueForKey:@"Name"] isEqualToString:nameString]) 
     { 
      index = i; 
      break; // << added break 
     } 
    } 
} 

[tmpMutArr replaceObjectAtIndex:index withObject:[NSDictionary dictionaryWithDictionary:mutDict]]; 

Answer 2

也許，你應該嘗試這個版本...你還沒有指定需要哪個索引，我想是第一個。

for (int i=0;i<[tmpMutArr count];i++) { 
    if([[tmpMutArr objectAtIndex:i] isKindOfClass:[NSDictionary class]]) { 
     NSMutableDictionary *tempDict = [tmpMutArr objectAtIndex:i]; 
     if([[tempDict valueForKey:@"Name"] isEqualToString:[NSString stringWithFormat:@"%@", nameString]]) { 
      index = i; 
      break; // when you find the first one, you should go out from the iteration 
     } 
    } 
}