的Java轉換的特殊字符串數組

Question

我想拆分此字符串

['1','BR_1142','12,345','01-02-2012', 'Test 1'],['2','BR_1142','12,345','01-02-2012', 'Test 2'] 

的陣列要陣列串的Java中的數組？

我可以用正則表達式來做還是應該寫一個遞歸函數來處理這個目的？

Answer 1

我不能對此進行測試，因爲最近的崩潰抹去取出所有我的程序，但我相信你可以使用JSON解析器來解析字符串。在解析之前，您可能必須將它包裝在[和]或{和}中。

見

• http://answers.oreilly.com/topic/257-how-to-parse-json-in-java/
• http://www.json.org/java/
• How to parse a JSON and turn its values into an Array?

Answer 2

如何像下面

String str= "['1','BR_1142','12,345','01-02-2012', 'Test 1'],['2','BR_1142','12,345','01-02-2012', 'Test 2']"; 

String[] arr = str.split("\\],\\["); 
String[][] arrOfArr = new String[arr.length][]; 
for (int i = 0; i < arr.length; i++) { 
    arrOfArr[i] = arr[i].replace("[", "").replace("]", "").split(","); 
} 

Answer 3

String yourString = "['1','BR_1142','12,345','01-02-2012', 'Test 1'],['2','BR_1142','12.345','01-02-2012', 'Test 2']"; 
yourString = yourString.substring(1, yourString.lastIndexOf("]")); 
String[] arr = yourString.split("\\],\\["); 

String[][] arr1 = new String[arr.length][]; 
int i = 0; 
String regex = "(?<=['],)"; // This regex will do what you want.. 
for(String a : arr) { 
    arr1[i++] = a.split(regex); 
} 

for (String[] arrasd: arr1) { 
    for (String s: arrasd) { 
     System.out.println(s.replace(",", "")); 
    } 
} 

Answer 4

你可以結合使用String.split和正則表達式look-behind：

String str = "['1','BR_1142','12,345','01-02-2012', 'Test 1'],['2','BR_1142','12,345','01-02-2012', 'Test 2']"; 
String[] outerStrings = str.split("(?<=]),"); 
String[][] arrayOfArray = new String[outerStrings.length][]; 

for (int i=0; i < outerStrings.length; i++) { 
    String noBrackets = outerStrings[i].substring(1, outerStrings[i].length() - 1); 
    arrayOfArray[i] = noBrackets.split(","); 
}