爲什麼switch語句無法根據需要打印字符串？ （Java）

Question

我已經被賦予打印我已經構建到控制檯的棋盤的任務。電路板的頂部必須有'a'到'h'，而左邊的是1到8。每個首字母應該與一個字母和一個數字對齊，例如，一個黑車（「bR」）應該放置在8處（並且應該在數組中初始化爲[0] [0]）。排除效率低下的明顯問題（應該爲頂部字符標籤使用char數組），爲什麼printBoard方法中的嵌套for循環無法將正確的位置的首字母打印到控制檯？

public class Virtual_Chessboard { 

    public enum Chessmen{ 
     WHITE_KING, 
     WHITE_QUEEN, 
     WHITE_ROOK, 
     WHITE_BISHOP, 
     WHITE_KNIGHT, 
     WHITE_PAWN, 
     BLACK_KING, 
     BLACK_QUEEN, 
     BLACK_ROOK, 
     BLACK_BISHOP, 
     BLACK_KNIGHT, 
     BLACK_PAWN, 
     EMPTY 
    } 

    public static Chessmen[][] chessboard = new Chessmen[8][8]; 

    public static void createBoard(){ 


     int rows = 8; 
     int columns = 8; 

     for(int y=0;y<rows;y++){ 
      for(int x=0;x<columns;x++){ 
       if((y==0 && x==0) || (x==7 && y==0)){ 
        chessboard[x][y] = Chessmen.BLACK_ROOK; 
       } 
       else if((x==1 && y==0)||(x==6 && y==0)){ 
        chessboard[x][y] = Chessmen.BLACK_KNIGHT; 
       } 
       else if((x==2 && y==0)||(x==5 && y==0)){ 
        chessboard[x][y] = Chessmen.BLACK_BISHOP; 
       } 
       else if(x==3 && y==0){ 
        chessboard[x][y] = Chessmen.BLACK_KING; 
       } 
       else if(x==4 && y==0){ 
        chessboard[x][y] = Chessmen.BLACK_QUEEN; 
       } 
       else if((x==0 && y==7)||(x==7 && y==7)){ 
        chessboard[x][y]= Chessmen.WHITE_ROOK; 
       } 
       else if((x==1 && y==7)||(x==6 && y==7)){ 
        chessboard[x][y] = Chessmen.WHITE_KNIGHT; 
       } 
       else if((x==2 && y==7)||(x==5 && y==7)){ 
        chessboard[x][y] = Chessmen.WHITE_BISHOP; 
       } 
       else if(x==3 && y==7){ 
        chessboard[x][y] = Chessmen.WHITE_KING; 
       } 
       else if(x==4 && y==7){ 
        chessboard[x][y] = Chessmen.WHITE_QUEEN; 
       } 
       else if(y==1){ 
        chessboard[x][y] = Chessmen.BLACK_PAWN; 
       } 
       else if(y==6){ 
        chessboard[x][y] = Chessmen.WHITE_PAWN; 
        } 
       else{ 
        chessboard[x][y] = Chessmen.EMPTY; 
       } 
      } 
     } 
    } 

    public static void printBoard(Chessmen[][] chessboard){ 
     int k = 8; 
     System.out.print("\t"+"a" + "\t" + "b" + "\t" + "c" + "\t" + "d" + "\t" + "e"+ "\t" + "f" + "\t" + "g" + "\t" + "h" + "\n" + k); 
     for(int i = 0; i<8;i++){ 
      for(int j = 0;j<1;j++){ 
       System.out.print("\t"); 
       switch(chessboard[i][j]){ 
       case WHITE_KING : System.out.print("WK"); 
       case WHITE_QUEEN : System.out.print("wQ"); 
       case WHITE_ROOK : System.out.print("wR"); 
       case WHITE_BISHOP : System.out.print("wB"); 
       case WHITE_KNIGHT : System.out.print("wK"); 
       case WHITE_PAWN : System.out.print("wP"); 
       case BLACK_KING : System.out.print("BK"); 
       case BLACK_QUEEN : System.out.print("bQ"); 
       case BLACK_ROOK : System.out.print("bR"); 
       case BLACK_BISHOP : System.out.print("bB"); 
       case BLACK_KNIGHT : System.out.print("bK"); 
       case BLACK_PAWN : System.out.print("bP"); 
       case EMPTY : System.out.print("\t"); 
       } //switch 

      } /// j for 

      k--; 
      System.out.println("\n"+k); 
     } //i for 

    } 

    public static void main(String[] args) { 


     createBoard(); 
     printBoard(chessboard); 

    } 

} 

Answer 1

你必須終止每case聲明以break開關塊結束後繼續執行。否則，你會進入下一個案例陳述。

Answer 2

您的EMPTY情況正在打印「\ t」。這將會關閉你的列。沒有其他類型的打印機可以打印\ t，並且您可以在循環中打印它。因此，它應該只是打印（「」）;