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我想開始使用OpenAL。C++:AL/altypes.h沒有這樣的文件或目錄
我試圖編譯這個程序,我用從here有:
g++ main.cpp -lOpenAL
此刻的錯誤"AL/altypes.h" No such file or directory.
出現。有誰知道我該如何解決這個問題?我已安裝libopenal-dev
。 (我在Ubuntu 13.04,我認爲?)
#include <iostream>
#include <cstdlib>
#include <AL/altypes.h>
#include <AL/al.h>
#include <AL/alu.h>
#include <AL/alut.h>
#define NUM_BUFFERS 1
#define NUM_SOURCES 1
#define NUM_ENVIRONMENTS 1
ALfloat listenerPos[] = {0.0, 0.0, 4.0};
ALfloat listenerVel[] = {0.0, 0.0, 0.0};
ALfloat listenerOri[] = {0.0, 0.0, 1.0, 0.0, 1.0, 0.0};
ALfloat source0Pos[] = {0.0, 0.0, 0.0};
ALfloat source0Vel[] = {0.0, 0.0, 0.0};
ALuint buffer[NUM_BUFFERS];
ALuint source[NUM_SOURCES];
ALuint environment[NUM_ENVIRONMENTS];
ALsizei size, freq;
ALenum format;
ALvoid* data;
void init(void)
{
alListenerfv(AL_POSITION,listenerPos);
alListenerfv(AL_VELOCITY,listenerVel);
alListenerfv(AL_ORIENTATION,listenerOri);
alGetError(); // clear any error messages
// Generate buffers, or else no sound will happen!
alGenBuffers(NUM_BUFFERS, buffer);
if(alGetError() != AL_NO_ERROR)
{
std::cout << "- Error creating buffers !!" << std::endl;
exit(1);
}
else
{
std::cout << "init() - No errors yet." << std::endl;
}
alutLoadWAVFile((Albyte *) "c.wav", &format, &data, size,&freq, &al_bool);
alBufferData(buffer[0],format,data,size,freq);
alutUnloadWAV(format,data,size,freq);
alGetError(); /* clear error */
alGenSources(NUM_SOURCES, source);
if(alGetError() != AL_NO_ERROR)
{
std::cout << "- Error creating sources !!" << std::endl;
exit(2);
}
else
{
std::cout << "init - no errors after alGenSources" << std::endl;
}
alSourcef(source[0], AL_PITCH, 1.0f);
alSourcef(source[0], AL_GAIN, 1.0f);
alSourcefv(source[0], AL_POSITION, source0Pos);
alSourcefv(source[0], AL_VELOCITY, source0Vel);
alSourcei(source[0], AL_BUFFER,buffer[0]);
alSourcei(source[0], AL_LOOPING, AL_TRUE);
}
int main()
{
//initialise openAL
alutInit(&argc, argv) ;
init();
return 0;
}
順便說一句,這個程序實際上不會做我想做的時刻。
我想聲明一個double/int數組,填充數據並播放該數據。有誰知道我該怎麼做?