刪除*從表不工作

Question

我想從表中刪除所有行，但它不工作。當我做echo $mydb->error; 它給了我下面的：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '* FROM messages where from_user = ? and id = ?'

 $user = 'currentuser'; 
if (isset($_POST['delete'])) { 
if(!empty($_POST['id'])){ 
$id = $_POST['id']; 


$mydb = new mysqli('localhost', 'root', '', 'database'); 
$stmt = $mydb->prepare("DELETE * FROM messages where from_user = ? and id = ? "); 
echo $mydb->error; 
$stmt->bind_param('ss', $user, $id); 
foreach ($_POST['id'] as $id) { 
$stmt->execute(); 
} 
echo"The Message deleted permanently"; 
} 
} 

Answer 1

應該

$stmt = $mydb->prepare("DELETE FROM messages WHERE from_user = ? AND id = ? "); 

而且我會很高興使用mysqli_*功能，而不是過時mysql_*

加，DELET不應該有* Ë;這不是正確的語法。

參考：

• https://dev.mysql.com/doc/refman/5.0/en/delete.html

的*語法配合使用SELECT：

• https://dev.mysql.com/doc/refman/5.0/en/select.html

Answer 2

如果你婉T刪除該用戶的所有消息：

$stmt = $mydb->prepare("DELETE FROM messages where from_user = ?"); 
$stmt->bind_param('s', $user); 
$stmt->execute(); 

如果你想從表中刪除所有行（小心！）：

$stmt = $mydb->prepare("DELETE FROM messages"); 
$stmt->execute();