PDO刪除不工作

Question

<?php 
$db = new PDO('mysql:host=localhost;dbname=wordpress', 'root',''); 
//---------prepare 
$delete3 = $db->prepare("DELETE FROM wp_term_relationships WHERE object_id=:id"); 
$delete2 = $db->prepare("DELETE FROM wp_posts WHERE ID=:id"); 
$delete = $db->prepare("DELETE FROM wp_postmeta WHERE post_id=:id");; 
$select = $db->prepare("SELECT post_id FROM reference WHERE x_id=?"); 
$delete->bindParam(':id', $id, PDO::PARAM_STR); 
$delete2->bindParam(':id', $id, PDO::PARAM_STR); 
$delete3->bindParam(':id', $id, PDO::PARAM_STR); 
//---------- 
echo 'conected-----'; 
{$delfeed = 'LOTS OF NUMBERS';} 
$array = explode(',',$delfeed); 
foreach($array as $deadman){ 
    $select->execute(array($deadman)); 
    $row = $select->Fetch(PDO::FETCH_ASSOC); 
    $id = $row['post_id']; 
     if ($id){ 
     echo "$id"."\n"; 
     $delete->execute(); 
     $delete2->execute(); 
     $delete3->execute(); 
}} 
echo 'done!'; 
?> 

其簡單刪除腳本，但它不刪除，它打印正確的$ id的女巫意味着正在工作，直到有但刪除雲香蕉，雙重檢查表名，colums ... tryied與問號佔位工作insted的綁定參數，但沒有 更新的：它粘在陣列中的foreach

Answer 1

問題的第一個項目是，你設置$id變量是有史以來之前。

<?php 
$db = new PDO('mysql:host=localhost;dbname=wordpress', 'root',''); 

$delete3 = $db->prepare("DELETE FROM wp_term_relationships WHERE object_id=?"); 
$delete2 = $db->prepare("DELETE FROM wp_posts WHERE ID=?"); 
$delete = $db->prepare("DELETE FROM wp_postmeta WHERE post_id=?"); 
$select = $db->prepare("SELECT post_id FROM reference WHERE x_id=?"); 

foreach($array as $deadman){ 
    $select->execute(array($deadman)); 
    $row = $select->Fetch(PDO::FETCH_ASSOC); 
    $id = $row['post_id']; 
    if ($id) { 
     echo "$id"."\n"; 
     $data = array($id); 
     $delete->execute($data); 
     $delete2->execute($data); 
     $delete3->execute($data); 
    } 
    $id++; 
} 
echo 'done!'; 
?> 

我沒有更新你的代碼一點點，因爲一些位沒有意義，如$delfeed是一個空字符串，增加，即使它被覆蓋了$id變量，且放置隨意左右大括號。但正如你所看到的，在if($id)的檢查中，我將變量綁定在那裏。

除了使用我的方法，您可以指定文檔頂部的變量$id爲值0;然後，在完成所有準備說明之後，您可以使用功能bindParam而不是bindValue。

$id = 0; 

// Prepare Statements 

$delete->bindParam(':id', $id, PDO::PARAM_STR); 
$delete2->bindParam(':id', $id, PDO::PARAM_STR); 
$delete3->bindParam(':id', $id, PDO::PARAM_STR); 

// Rest of Original Code With No Changes 

這部作品的原因，是因爲bindParam經過在查詢執行時間參考。見PHP bindParam Document以及this answer.

編輯：解決方案的2個固定的foreach問題

<?php 
$db = new PDO('mysql:host=localhost;dbname=wordpress', 'root',''); 

$delete3 = $db->prepare("DELETE FROM wp_term_relationships WHERE object_id=:id"); 
$delete2 = $db->prepare("DELETE FROM wp_posts WHERE ID=:id"); 

// Had a double semicolon trailing the function. Removed one of them 
$delete = $db->prepare("DELETE FROM wp_postmeta WHERE post_id=:id"); 
$select = $db->prepare("SELECT post_id FROM reference WHERE x_id=?"); 

$id = 0; // Define Variable BEFORE bindParam 

$delete->bindParam(':id', $id, PDO::PARAM_STR); 
$delete2->bindParam(':id', $id, PDO::PARAM_STR); 
$delete3->bindParam(':id', $id, PDO::PARAM_STR); 


$delfeed = ''; // Why Have Curly Braces around this? 

$array = explode(',',$delfeed); 

foreach($array as $deadman) { 
    $select->execute(array($deadman)); 
    $row = $select->Fetch(PDO::FETCH_ASSOC); 
    $id = $row['post_id']; 
    if ($id){ 
     echo "$id"."\n"; 
     $delete->execute(); 
     $delete2->execute(); 
     $delete3->execute(); 
    } 
} 
echo 'done!'; 
?>