PHP/MySQL的使用ORDER BY與LIMIT

Question

我大致由以下鏈接創建一個分頁：

http://www.awcore.com/dev/1/3/Create-Awesome-PHPMYSQL-Pagination_en#toggle

很涼爽。雖然我的查詢有問題。

它工作正常，像這樣：

require 'includes/function.php'; 

    $page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]); 
    $limit = 8; 
    $startpoint = ($page * $limit) - $limit; 

    $statement = "cars WHERE deleted = 'no'"; 

$query = mysql_query("SELECT * FROM {$statement} LIMIT {$startpoint}, {$limit} "); 

while ($row = mysql_fetch_assoc($query)) { 

然而，當我試圖加一個ORDER BY這一點，像這樣：

需要 '包括/ function.php';

$page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]); 
    $limit = 8; 
    $startpoint = ($page * $limit) - $limit; 

    $statement = "cars WHERE deleted = 'no'"; 

$query = mysql_query("SELECT * FROM {$statement} LIMIT {$startpoint}, {$limit} ORDER BY model DESC"); 

while ($row = mysql_fetch_assoc($query)) { 

或者只是改變這樣的說法：

$statement = "rcr_cars WHERE deleted = 'no' ORDER BY model DESC"; 

我得到這個錯誤：79

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in filepath/myfile.php on line 79. 

行是這一行：

while ($row = mysql_fetch_assoc($query)) { 

誰能告訴我如何正確使用ORDER BY ，它讓我感到困惑。 ：/

Answer 1

嘗試查詢如下

$query = mysql_query("SELECT * FROM {$statement} ORDER BY model DESC LIMIT {$startpoint}, {$limit} "); 

在那裏你出了問題是限制應來ORDER BY後。 Read more

Answer 2

更改查詢：

$query = mysql_query("SELECT * FROM {$statement} ORDER BY model DESC LIMIT {$startpoint}, {$limit}") ; 

Answer 3

$query = mysql_query("SELECT * FROM {$statement} ORDER BY model DESC LIMIT {$startpoint}, {$limit} ");