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Question

控制器提取來自深度嵌套的關聯數據，其中bilancino belongs_to :operativo這反過來belongs_to :cdg這樣：

@cdgs = Cdg.order("id ASC").all 
@bilancinos = Bilancino.joins(:operativo).order('cdg_id ASC').all 

（具有where子句中存在）。渲染

<% @cdgs.each do |cdg| %> 
    <% @cdgs_for_bilancino = @bilancinos.select{ |i| i.operativo.cdg_id == cdg } %> 
    <%= @cdgs_for_bilancino.each do |bilancino| %> XX <% end %> 
    <%= number_with_precision(@cdgs_for_bilancino.map(&:saldo).sum, :precision => 0, :delimiter => "\u00a0") %> 
<% end %> 

當

然而正在生成一個空數組，但如果下方以下

<% @bilancinos.each do |bilancino| %> 
    <%= bilancino.operativo.cdg.conto %> <%= bilancino.saldo %><br /> 
<% end %> 

將呈現。因此，表達式@bilancinos.select{ |i| i.operativo.cdg_id以某種方式缺少嵌套目標。

什麼是正確的語法？

Answer 1

我懷疑你的問題是在這裏：

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例如，這是我在我的應用程序之一的控制檯中看到：

irb(main):022:0> recruiter = Recruiter.find_by_id(1) 
    Recruiter Load (0.9ms) SELECT "recruiters".* FROM "recruiters" WHERE "recruiters"."id" = $1 LIMIT 1 [["id", 1]] 
=> #<Recruiter id: 1> 
irb(main):023:0> ping = Ping.find_by_id(1) 
    Ping Load (0.9ms) SELECT "pings".* FROM "pings" WHERE "pings"."id" = $1 LIMIT 1 [["id", 1]] 
=> #<Ping id: 1, recruiter_id: 1> 
irb(main):024:0> recruiter.pings.select{ |p| p.id == ping } 
    Ping Load (0.5ms) SELECT "pings".* FROM "pings" WHERE "pings"."recruiter_id" = $1 [["recruiter_id", 1]] 
=> [] 
irb(main):025:0> recruiter.pings.select{ |p| p.id == ping.id } 
=> [#<Ping id: 1, recruiter_id: 1>] 

所以嘗試：

@bilancinos.select{ |i| i.operativo.cdg_id == cdg.id }