指定從JSON獲得的變量

Question

我瞎了嗎？爲什麼我不能從這個變量中得到這個值到我的變量'progress'中？ 它沒有保存爲一個字符串，'obj.songProgress [i] .songProgress'輸出到控制檯，但它自己的進度不會。進一步變量被分配好。

$(document).on("click",".profTemp", function() 
      {  

       if(!$(this).hasClass('selected')) 
       { 

       var selectedUser; 
       var previous = null; 
       var current = null; 
       var assigned = false; 
       var currentSong; 
       var previousSong; 
       var previousUser = null; 

       selectedUser = $(this).children('span').text(); 
       selectedUser = selectedUser.trim(); 

       $('.profTemp').removeClass('selected'); 
       clearInterval(pollUser); 

       $(this).toggleClass('selected'); 

       pollUser = setInterval(function() 
       { 
        console.log(selectedUser); 
        $.ajax({ 
        url: '/getJSON', 
        dataType: 'json', 
        success: function(response) { 
         obj = JSON.parse(response); 
         var changeTo; 
         var deviceID; 
         var playing; 
         var progress; 


         for(var i = 0; i < obj.clients.length; i++) 
         { 
          if(selectedUser == obj.clients[i].userName) 
          { 
          console.log(selectedUser + " inside if"); 
          current = JSON.stringify(obj.clients[i]); 
          changeTo = obj.clients[i].uri; 
          device = obj.clients[i].deviceID 
          playing = obj.clients[i].isPlaying; 
          currentSong = obj.clients[i].songName;          
          } 
         } 

         for(var i = 0; i < obj.songProgress.length; i++) 
          { 
          if(selectedUser == obj.songProgress[i].userName) 
          { 
           progress = obj.songProgress[i].songProgress; 
           console.log(obj.songProgress[i].songProgress + progress); 
          }        
          } 

這裏的JSON：

{ 
    "clients":[ 
     { 
     "userName":"test1 test1", 
     "albumArt":"https://i.scdn.co/image/e0f8a9160f4eaf4bee5816ca6f7833acbabf67ce", 
     "songName":"Everyday", 
     "artistName":"Angie Stone", 
     "albumName":"Black Diamond", 
     "songLength":1498831947299, 
     "isPlaying":false, 
     "uri":"spotify:track:7okKZ5JfRIJBcqKhX2fTmU", 
     "deviceID":"0a00d5d75dc4809ed68b92b4d998e71f36a69041", 
     "trackID":"7okKZ5JfRIJBcqKhX2fTmU", 
     "songProgress":101580 
     }, 
     { 
     "userName":"testaccount", 
     "albumArt":"https://i.scdn.co/image/1aa6bb570db21d1b5edd3071e39c8ac0530dd99d", 
     "songName":"Tyrant (feat. Jorja Smith)", 
     "artistName":"Kali Uchis", 
     "albumName":"Tyrant (feat. Jorja Smith)", 
     "songLength":1498832434724, 
     "isPlaying":true, 
     "uri":"spotify:track:6u24cRDn2mTKcXxxtgmIsV", 
     "deviceID":"2198676338ce85949579e2d6350962b6552bbbf5", 
     "trackID":"6u24cRDn2mTKcXxxtgmIsV", 
     "songProgress":1501 
     } 
    ], 
    "songProgress":[ 
     { 
     "userName":"test1 test1", 
     "songProgress":101580 
     }, 
     { 
     "userName":"testaccount", 
     "songProgress":1501 
     } 
    ] 
} 

Answer 1

的console.log（obj.songProgress [I] .songProgress +進展）; 上面的狀態是添加數據並給你總結數據。

檢查答案的小提琴https://jsfiddle.net/hnofbq8m/

if(selectedUser == obj.songProgress[i].userName) 
    { 
    progress = obj.songProgress[i].songProgress; 
    console.log(obj.songProgress[i].songProgress, progress); 
    }