mysql select不工作IN IN

Question

BEGIN 
DECLARE cnt1 int(11); 
DECLARE cnt2 int(11); 
DECLARE demandid varchar(255); 
set demandid = replace(pintypeid,';',','); 

SELECT 
    COUNT(*) into cnt1 
FROM 
    UK_Generic_Demand_Details 
where status =300 and 
policyNumber =pinpno and 
demandTypeId in(Select @demandid) ; 

    SELECT 
    COUNT(*) into cnt2 
FROM 
    UK_Generic_Completed_Demand_Details 
    where 
     status =300 and 
policyNo =pinpno and 
demandTypeId in(select @demandid); 
     select cnt1+cnt2 into poutcount; 

END 

可以請一些建議我解決這個問題。 存儲過程將從應用程序調用pintypeid和policynumber作爲輸入。 policynumber將單個，但pintypeid將像一個字符串。

Answer 1

您可能正在尋找find_in_set

BEGIN 
DECLARE cnt1 int(11); 
DECLARE cnt2 int(11); 
DECLARE demandid varchar(255); 
set demandid = replace(pintypeid,';',','); 

SELECT 
    COUNT(*) into cnt1 
FROM 
    UK_Generic_Demand_Details 
where status =300 and 
policyNumber =pinpno and 
find_in_set(demandTypeId, @demandid) > 0; 

    SELECT 
    COUNT(*) into cnt2 
FROM 
    UK_Generic_Completed_Demand_Details 
    where 
     status =300 and 
policyNo =pinpno and 
find_in_set(demandTypeId, @demandid) > 0; 
     select cnt1+cnt2 into poutcount; 

END