我試圖使用sqlfiddle v 5.6或MySQL Workbench v5.7創建視圖以包含來自表CUSTOMERS的所有信息,但將firstName和lastName連接爲wholeName。 我使用以下嘗試:如何在MySql中創建視圖時使用select *和concat
CREATE VIEW v_customer AS SELECT *,
CONCAT(CONCAT(lastName, ', '), firstName AS wholeName,
FROM customers;
和
CREATE VIEW v_customer AS SELECT customerID,
CONCAT(CONCAT(lastName, ', '), firstName AS wholeName,
...(all other customer columns),
FROM customers;
當離開了CONCAT功能,創建視圖。它使我相信我的語法有問題,但是錯誤在「FROM」行提出。
謝謝。我發佈了對我有用的東西,但是這也適用。 – Halston