幫助按訂單排序並顯示訂單

Question

以下是我爲Sqlite編寫的bash腳本。

#!/bin/bash 
sqlite3 file.db "CREATE TABLE table1(name text,rolln integer PRIMARY KEY,examm integer CHECK(examm >=0 and examm <= 50));" 
sqlite3 file.db "insert into table1(name,rolln,examm)values('Aldose Paul ',1234,'alpj@gmail.com',49); " 
sqlite3 file.db "insert into table1(name,rolln,examm)values('Thomas Paul',1023,'tpaul@gmail.com',45); " 

sqlite3 file.db "CREATE TABLE project(title text PRIMARY KEY,marks integer CHECK(marks >= 0 and marks <= 20)) ;" 
sqlite3 file.db "insert into project(title,marks)values('A',16);" 
sqlite3 file.db "insert into project(title,marks)values('B',14);" 


sqlite3 file.db "select rolln AS 'Roll Number' ,(examm) AS 'Total Marks'from table1 order by (examms) ;" 

Answer 1

擔任首發，這裏是讓根據等級排名的一種方式：

.headers on 

create table foo (name text, grade int); 

insert into foo values ('Joe', 45); 
insert into foo values ('Anna', 98); 
insert into foo values ('Julie', 78); 

select name, 
     grade, 
     (select count(*) from foo t1 where t1.grade>=t2.grade) as rank 
from foo t2; 

select name, 
     grade, 
     (select count(*) from foo t1 where t1.grade>=t2.grade) as rank 
from foo t2 
order by rank; 

救以此爲foo.sql，我得到這個：

[someone@somewhere tmp]$ sqlite3 < foo.sql 
name|grade|rank 
Joe|45|3 
Anna|98|1 
Julie|78|2 
name|grade|rank 
Anna|98|1 
Julie|78|2 
Joe|45|3